Instructions: Answer the following and show your solution. Round off all numerical answers to three (3) significant figures. 1.) Consider the following redox reaction: Zn + Cu (aa) → Zn²"(aa) + Culs) What is the value of the chemical equilibrium constant? E"zn2+/Zn) = -0.763 v E'(Cu2-/Cu) = +0.337 V 2.) Consider the following redox reaction: Als) + Fe" (aa) → Al (aq) + Fes) What is the value of the chemical equilibrium constant? E(AIB+/AI) = -1.662 V E°Fe3+/Fe) = -0.440 V

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Instructions: Answer the following and show your solution. Round off all numerical answers to three (3)
significant figures.
1.) Consider the following redox reaction:
Zn + Cu (a) → Zn (aa) + Culs)
What is the value of the chemical equilibrium constant?
E"zn2+/Zn) = -0.763 v
E'(Cu2-/Cu) = +0.337 V
2.) Consider the following redox reaction:
Al + Fe" (aa) → Al (aq) + Fes)
What is the value of the chemical equilibrium constant?
E'AB-/AI) = -1.662 V
E' Fe3+/Fe) = -0.440 v
3.) Calculate the cell potentials and construct a titration curve for the titration of 50.0 ml of 0.1000
M Fe* with 0.05000 M Sn2.
Fe* + le → Fe?+
E'Fe3/Fe2+) = +0.771 v
Sn** + 2e → Sn²+
E" Sne+/Sn2-) = +0.154 V
Vol. Sn (mL): 10.00, 25.00, 49.00, 49.90, 50.00, 50.10, 51.00, 60.00
4.) Calculate the cell potentials and construct a titration curve for the titration of 50.0 ml of 0.1000
M V* with 0.05000M Sn*.
V³* + 1e → V
Snt + 2e → Sn2+
E°va-/v2+) = -0.256 V
E"snd+/Sn2+) = +0.154 V
Vol. Sn** (mL): 10.00, 25.00, 49.00, 49.90, 50.00, 50.10, 51.00, 60.00
Transcribed Image Text:Instructions: Answer the following and show your solution. Round off all numerical answers to three (3) significant figures. 1.) Consider the following redox reaction: Zn + Cu (a) → Zn (aa) + Culs) What is the value of the chemical equilibrium constant? E"zn2+/Zn) = -0.763 v E'(Cu2-/Cu) = +0.337 V 2.) Consider the following redox reaction: Al + Fe" (aa) → Al (aq) + Fes) What is the value of the chemical equilibrium constant? E'AB-/AI) = -1.662 V E' Fe3+/Fe) = -0.440 v 3.) Calculate the cell potentials and construct a titration curve for the titration of 50.0 ml of 0.1000 M Fe* with 0.05000 M Sn2. Fe* + le → Fe?+ E'Fe3/Fe2+) = +0.771 v Sn** + 2e → Sn²+ E" Sne+/Sn2-) = +0.154 V Vol. Sn (mL): 10.00, 25.00, 49.00, 49.90, 50.00, 50.10, 51.00, 60.00 4.) Calculate the cell potentials and construct a titration curve for the titration of 50.0 ml of 0.1000 M V* with 0.05000M Sn*. V³* + 1e → V Snt + 2e → Sn2+ E°va-/v2+) = -0.256 V E"snd+/Sn2+) = +0.154 V Vol. Sn** (mL): 10.00, 25.00, 49.00, 49.90, 50.00, 50.10, 51.00, 60.00
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