•• INT An electron is launched at a 45° angle and a speed of 5.0 x 10° m/s from the positive plate of the parallel-plate capacitor shown in Figure P23.52º. The electron lands 4.0 cm away. Figure P23.52 4.0 cm a. What is the electric field strength inside the capacitor? b. What is the smallest possible spacing between the plates?

•• INT An electron is launched at a 45° angle and a speed of 5.0 x 10° m/s from the positive plate of the parallel-plate capacitor shown in Figure P23.52º. The electron lands 4.0 cm away. Figure P23.52 4.0 cm a. What is the electric field strength inside the capacitor? b. What is the smallest possible spacing between the plates?

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter18: Electric Charge And Electric Field

Section: Chapter Questions

Problem 53PE: A simple and common technique for accelerating electrons is shown in Figure 18.55, where there is a...

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Review. From a large distance away, a particle of mass m1, and positive charge q1 is fired at speed in the positive x direction straight toward a second particle, originally stationary but free to move, with mass m2, and positive charge q2. Both particles are constrained to move only along the x axis. (a) At the instant of closest approach, both particles will be moving at the same velocity. Find this velocity, (b) Find the distance of closest approach. After the interaction, the particles will move far apart again. At this time, find the velocity of (c) the particle of mass m1, and (d) the particle of mass m2.
Integrated Concepts Figure 18.57 shows an electron passing between two charged metal plates that create an 100 N/C vertical electric field perpendicular to the electron's original horizontal velocity. (These can be used to change the electron’s direction, such as in an oscilloscope.) The initial speed of the electron is 3.00106 m/s, and the horizontal distance it travels in the uniform field is 4.00 cm. (a) What is its vertical deflection? (b) What is the vertical component of its final velocity? (c) At what angle does it exit? Neglect any edge effects.
The electric field along the axis of a uniformly charged disk of radius R and total charge Q was calculated in Example 23.3. Show that the electric field at distances x that are large compared with R approaches that of a particle with charge Q = R2. Suggestion: First show that x/(x2 + R2)1/2 = (1 + R2/x2)1/2 and use the binomial expansion (1 + )n = 1 + n, when 1.
Construct Your Own Problem Consider two insulating balls with evenly distributed equal and opposite charges on their surfaces, held with a certain distance between the centers of the balls. Construct a problem in which you calculate the electric field (magnitude and direction) due to the balls at various points along a line running through the centers of the balls and extending to infinity on either side. Choose interesting points and comment on the meaning of the field at those points. For example, at what points might the field be just that due to one ball and where does the field become negligibly small? Among the things to be considered are the magnitudes of the charges and the distance between the centers of the balls. Your instructor may wish for you to consider the electric field off axis or for a more complex array of charges, such as those in a water molecule.
Cathode ray tubes (CRTs) used in old-style televisions have been replaced by modern LCD and LED screens. Part of the CRT included a set of accelerating plates separated by a distance of about 1.50 cm. If the potential difference across the plates was 25.0 kV, find the magnitude of the electric field in the region between the plates.
Construct Your Own Problem Consider identical spherical conducting space ships in deep space where gravitational fields from other bodies are negligible compared to the gravitational attraction between the ships. Construct a problem in which you place identical excess charges on the space ships to exactly counter their gravitational attraction. Calculate the amount of excess charge needed. Examine whether that charge depends on the distance between the centers of the ships, the masses of the ships, or any other factors. Discuss whether this would be an easy, difficult, or even impossible thing to do in practice.
a point charge of magnitude 5.00 C is at the origin of a coordinate system, and a charge of 4.00 C is at the point x = 1.00 m. There is a point on the x-axis, at x less than infinity, where the electric field goes to zero. (a) Show by conceptual arguments that this point cannot be located between the charges. (b) Show by conceptual arguments that point cannot be at any location between x = 0 and negative infinity. (c) Show by conceptual arguments that the point must be between x = 1.00 m and x = positive infinity. (d) Use the values given to find the point and show that it is consistent with your conceptual argument.
Why does a car always attract dust right after it is polished? (Note that car wax and car tires are insulators.)
Two charges 20Cand+2.0C are separated by 4.0 cm on the z-axis symmetrically about origin, with the positive one uppermost. Two space points of interest and P1andP2 are located 3.0 cm and 30 cm from origin at an angle 30 with respect to the z-axis. Evaluate electric potentials at P1andP2 and in two ways: (a) Using the exact formula for point charges, and (b) rising the approximate dipole potential formula.
(a) Using the symmetry of the arrangement, show that the electric field at the center of the square in figure 18.46 is zero if the charges on the four comers are exactly equal. (b) Show that this is also true for any combination of charges in which qa= qd and qa = qc
A simple and common technique for accelerating electrons is shown in Figure 18.55, where there is a uniform electric field between two plates. Electrons are released, usually from a hot filament, near the negative plate, and there is a small hole in the positive plate that allows the electrons to continue moving. (a) Calculate the acceleration of the electorn if the field strength is 2.50104 N/C. (b) Explain why the electron will not be pulled back to the positive plate once it moves through the hole.
Before liquid crystal display LCD computer and television screens, the screens were cathode-ray tube CRTS, in which a bean of electrons was shot towards a Phosphorescent screen at high speed and deflected by electric fields in order to direct the beam to the right place on the screen so that it would form the picture. In a typical television, the speed of the electrons is 1 x10^8 m/s. If the television set is placed so that the CRT beam is horizontal heading east in a place where the earths magnetic field is 5×10^-5 and points horizontally northward what will be the magnetic force on the electron?