80umution)edIumlution)400010080IR Spectrum(KBr disc)604020% of base peak10301104013C NMRSpectrum(100.0 MHz,D₂O solution)proton decoupled200¹H NMR Spectrum(400 MHz. D₂0 solution)Note: there are 3 protonswhich exchange withthe D₂O solvent3.230003.092000M+= 103120expansionsppm80m/eDEPT CH₂ CH₂ CH16081600V (cm¹)16001601200800Mass SpectrumC4H₂NO₂200 240 280120Problem 21No significant UVabsorption above 220 nm4008 (ppm)08 (ppm80H₂O and HODin solvent2.2 2.0ppm117 6 5 4 3 2 1

Answered: Image /qna-images/answer/f1041b05-a0f2-44aa-a345-6664bf74d74f.jpg

IR Spectrum (KBr disc) ستا 4000 100 80 60 20 % of base peak 13C NMR Spectrum (100.0 MHz, D₂0 solution) 30 40 yu 3.0 3000 proton decoupled 200 ¹H NMR Spectrum (400 MHz. D₂0 solution) Note: there are 3 protons which exchange with the D₂0 solvent 3.2 2000 expansions ppm 1600 M+= 103 80 120 160 m/e DEPT CH₂ CH₂ CH 160 1600 V (cm¹) 2.2 200 120 2.0 ppm J 800 Mass Spectrum 1200 C4H₂NO₂ 280 240 80 H₂O and HOD in solvent Problem 21 No significant UV absorption above 220 nm 40 2 08 (ppm) 1 0 loom

IR Spectrum (KBr disc) ستا 4000 100 80 60 20 % of base peak 13C NMR Spectrum (100.0 MHz, D₂0 solution) 30 40 yu 3.0 3000 proton decoupled 200 ¹H NMR Spectrum (400 MHz. D₂0 solution) Note: there are 3 protons which exchange with the D₂0 solvent 3.2 2000 expansions ppm 1600 M+= 103 80 120 160 m/e DEPT CH₂ CH₂ CH 160 1600 V (cm¹) 2.2 200 120 2.0 ppm J 800 Mass Spectrum 1200 C4H₂NO₂ 280 240 80 H₂O and HOD in solvent Problem 21 No significant UV absorption above 220 nm 40 2 08 (ppm) 1 0 loom

Principles of Instrumental Analysis

7th Edition

ISBN:9781305577213

Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Chapter20: Molecular Mass Spectrometry

Section: Chapter Questions

Problem 20.11QAP

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Answer Q40, 41, 42 showing detailly all explanations
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