8Please with provided formula easy way to explain please 7. A 2-kg object moving to the right with velocity 5 m/s collides with a 3-kg object which is initially at rest. After thecollision, the 3-kg object has a velocity vector y = i-j. What is the speed of the 2-kg object after the collision?A) 0.8 m/sB) 1.8 m/sC) 2.8 m/sD) 3.8 m/sE) 4.8 m/s8. If 15 J of potential energy are stored in a spring which has been compressed by 2 cm from its relaxed length, how muchforce will this spring exert if it is stretched by 4 cm from its relaxed length?A) 500 NB) 3000 NC) 7500 ND) 75,000 NE) None of the Abovemass of 10 kg is attached to the spring in problem 8. The spring is compressed by 2 cm and is released. When thespring reaches its equilibrium position, whatthe speed of the 10-kg mass?A) 1 m/sB) 1.7 m/sC) 2 m/sD) 2.7 m/sE) 3 m/s3.S + 1.SS10. A toy car is on a small indoor track, which is 100-m in circumference. The car starts from rest, accelerates uniformly,and after 5 seconds reaches a point halfway around the circle.acceleration?this time, what is the magnitude of the car'sA) 4 m/sB) 9 m/sC) 16 m/sD) 25 m/sE) >25 m/s11. A 2-kg block starts from rest at the top of a 10-m long ramp inclined at 45 deg to the horizontal. The block is releasedand begins to slide down the ramp. At the bottom of the ramp the block has a speed of 9 m/s. What is the coefficient offriction between the block and the ramp?A) 0.12B) 0.22C) 0.32D) 0.42E) 0.5212.25+ 2.2514.5 v²Circular motion: a =RWPavr =ΔtFnet = ma;Weight: Fg = mg, ;g = 9.8 m/s?;1Kinetic energy: K = -m v²;2Potential energy: Ug=mgyE = ErE = U+Kv2Rotational motion:0 =1 rev = 2n rad;v = o r;a, == w?r;at = a r;r0 = 0o + at;0 = 0o t+2θα-ω - 02T=rxF;T= rFsino;Στ-Ια;Iy=ml1Ipoinț mass = mr?Iaisk =mR 21Irod(end) = -mL?2Ishell = =mR?3Ihoop = mR?Irod(center) =mL?Iball = =mR?12work: W=r0; K=-lo 2dWP =dtI= Icom + MD²W =Pavr =At1m Vcom ?Rolling:2K =2Vcom = RoT= f,RF,max = H,FnIncline: Fg=mgsin0 F mgcos0Angular momentum:Lpoint mass = m rxvL= mrysin 0:L=m (r,vy - ryVx)kL= Iom¡X1+m2X2m, +m2LI = LrI 01 =I 202X commiy1+m2y2Y com =m1 +m212.257

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Jf 15 J of potential energy are stored in a spring which has been compressed by 2 cm from its relaxed length, how much force will this spring exert if it is stretched by 4 cm from its relaxed length? A) 500 N B) 3000 N C) 7500 N D) 75,000 N E) None of the Above

Jf 15 J of potential energy are stored in a spring which has been compressed by 2 cm from its relaxed length, how much force will this spring exert if it is stretched by 4 cm from its relaxed length? A) 500 N B) 3000 N C) 7500 N D) 75,000 N E) None of the Above

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter6: Momentum, Impulse, And Collisions

Section: Chapter Questions

Problem 77AP: (a) A car traveling due east strikes a car traveling due north at an intersection, and the two move...

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