)K.CrO CHO (+6) + 6e → 2Cr (+3) g wt K-CrOr g/mol = 49.03 g/eq %3D %3D 6 eq/mol HOz (as an HOz -1) + 2e → H2O (-2) oxidizing agent, reduce to Hz0) f=2 eg wt HO2 g/mol 2 eq/mol %3D 17.01 g/eq ASSIGNMENT Exercises: How to detemine the factor of reducing agent and oxidizing agent: 1. a. Fe b. HNO3 + H2S c. KMNO4 + LICI + H2SO4 d. KCr2O7 + KI + H3PO4 e. K2Cr2O7 f. MnO4 + g. MnO4 + HCI FeCla + H2 NO + H2O Ch +MnS04 + K2SO4 +LizSO4 +H2O K3PO4 + H20 2 + CrPO4 -> + FeSO4 +H2SO4 Fe *2 + H* C204 2 + H* Cr2(SO4)3 + Fe2(SO4]3 + K2SO4 + Fe3+ + CO2 H2C Mn** H2O +H2O Mn** 2 What fraction of the formula weight of each of the ff compounds represents th equivalent weight in a redox process in which the product formed is as indicate (a) Ce(SO4)2.2(NH4)2SO4.2H2O (→ Ce*) (b) As2Os ( As) (c) KIO3 (> ICk2)

Principles of Instrumental Analysis
7th Edition
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Chapter14: Applications Of Ultraviolet-visible Molecular Absorption Spectrometry
Section: Chapter Questions
Problem 14.6QAP: The accompanying data (1.00-cm cells) were obtained for the spectrophotometric titration 10.00 mL of...
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help me out pls with this one
K.CrO
CHOP (+6) + 6e
→ 2Cr (+3)
%3D
6 eq/mol
HO2 (as an
HOz -1) + 2e → H2O (-2)
oxidizing agent, reduce to Hz0)
f= 2
eg wt HO2 g/mol
2 eq/mol
%3D
17.01 g/eq
ASSIGNMENT
Exercises:
How to detemine the factor of reducing agent and oxidizing agent:
1.
HCI -
a. Fe
b. HNO3 + H2S
c. KMNO4 + LICI + H2SO4
d. KCr2O7 + KI + H3PO4
e. K2Cr2O7
f. MnO4 +
g. MnO4 +
FeCla +
H2
NO
+ H2O
Ch +MNSO4 + K2SO4
+LizSO4 +H2O
K3PO4 + Hz0
2 + CrPO4
->
+ FeSO4 +H2SO4
Fe *2 + H*
C204 2 + H*
Cr2(SO4)3 + Fe2(SO4)3 + KSO4
H2O
+H2O
H2O
Mn**
+ Fe3+
Mn**
+ CO2
2 What fraction of the formula weight of each of the ff compounds represents the
equivalent weight in a redox process in which the product formed is as indicated:
(a) Ce(SO4)2.2(NH4)2SO4.2H2O (→ Ce*)
(b) As2Os ( As)
(c) KIO3 (> ICk2)
Transcribed Image Text:K.CrO CHOP (+6) + 6e → 2Cr (+3) %3D 6 eq/mol HO2 (as an HOz -1) + 2e → H2O (-2) oxidizing agent, reduce to Hz0) f= 2 eg wt HO2 g/mol 2 eq/mol %3D 17.01 g/eq ASSIGNMENT Exercises: How to detemine the factor of reducing agent and oxidizing agent: 1. HCI - a. Fe b. HNO3 + H2S c. KMNO4 + LICI + H2SO4 d. KCr2O7 + KI + H3PO4 e. K2Cr2O7 f. MnO4 + g. MnO4 + FeCla + H2 NO + H2O Ch +MNSO4 + K2SO4 +LizSO4 +H2O K3PO4 + Hz0 2 + CrPO4 -> + FeSO4 +H2SO4 Fe *2 + H* C204 2 + H* Cr2(SO4)3 + Fe2(SO4)3 + KSO4 H2O +H2O H2O Mn** + Fe3+ Mn** + CO2 2 What fraction of the formula weight of each of the ff compounds represents the equivalent weight in a redox process in which the product formed is as indicated: (a) Ce(SO4)2.2(NH4)2SO4.2H2O (→ Ce*) (b) As2Os ( As) (c) KIO3 (> ICk2)
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