Km V. (V) 15) + V = [S] max a' = 2 a' = 1.5 (7) -15⁰° max a Vmax 1 [S] MM a'=1 [1]
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Given a graph for uncompetitive inhibition, where could we obtain a number that could be used to calculate:
a) Km
b) Vmax
(Need to know an exact location on the graph, but I don't understand how to go about this)
![Km
m
Km
V. - (K) ¹
max
a' = 1.5
μm/min/
-10°
[S] Vmax
+
a' = 2
Vmax
[S] MM
a'=1
[0]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4f69b949-129c-4dc3-b0d4-a9894ca2b873%2F46f9248c-a2f2-4a79-96ef-37d62e21ba78%2F6ans1dd_processed.jpeg&w=3840&q=75)
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