Please assign the missing products or reagents (A till E) in this scheme. KOC(CH3)aBr2BKOC(CH3)3NANH,DCH3IA-C=CCH3(2 equiv)DMSO

KOC(CH3)3 is known as Potassium tertiary butoxide. It is a highly hindered strong base generally…

Answered: KOC(CH3)3 Br2 KOC(CH3)3 NaNH2 CH3I D…

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KOC(CH3)3 Br2 KOC(CH3)3 NaNH2 CH3I D C=CCH3 (2 equiv) DMSO

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

Chapter10: Oxidation And Reduction

Section: Chapter Questions

Problem 10CTQ

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Question

Please assign the missing products or reagents (A till E) in this scheme.

KOC(CH3)a
Br2
B
KOC(CH3)3
NANH,
D
CH3I
A
-C=CCH3
(2 equiv)
DMSO

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