Lance administered a English Proficiency Exam to a random sample of 50 graduating students. In this sample, the mean is 94 and standard deviation is 8. The population parameter are μ=88 and σ=15. Does the sample come from the average population? Use α=0.05 and the p-value method. a. The null hypothesis is μ≤88 μ=88 μ>88 μ<88 b. The alternative hypothesis is μ≥88 μ=88 μ≠88 μ<88 c.The critical value is -1.645 1.96 -1.96 1.645 d. The kind of test is one-tailed two-tailed e. The test statistic to be used is p f z t f. The value of the test statistic is -2.50 2.83 2.50 -2.83 g. The p-value is 0.0046 0.002 0.001 0.0023 h. The Decision is Reject the null hypothesis. There is a significant difference between the sample mean and the population mean. Accept the null hypothesis.There is no significant difference between the sample mean and the population mean. Accept the null hypothesis.There is a significant difference between the sample mean and the population mean. Reject the null hypothesis. There is no significant difference between the sample mean and the population mean.
Lance administered a English Proficiency Exam to a random sample of 50 graduating students. In this sample, the
a. The null hypothesis is
μ≤88
μ=88
μ>88
μ<88
b. The alternative hypothesis is
μ≥88
μ=88
μ≠88
μ<88
c.The critical value is
-1.645
1.96
-1.96
1.645
d. The kind of test is
one-tailed
two-tailed
e. The test statistic to be used is
p
f
z
t
f. The value of the test statistic is
-2.50
2.83
2.50
-2.83
g. The p-value is
0.0046
0.002
0.001
0.0023
h. The Decision is
Reject the null hypothesis. There is a significant difference between the sample mean and the population mean.
Accept the null hypothesis.There is no significant difference between the sample mean and the population mean.
Accept the null hypothesis.There is a significant difference between the sample mean and the population mean.
Reject the null hypothesis. There is no significant difference between the sample mean and the population mean.
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