lat is the th CH,CH,OH + H,SO,→ CH,=CH, + H,0 OmL ethanol (MM: 46.07g/mol); ethylene (MM: 28.05); 30mL sulfuric acid 10 x 0.789g/mol = (7.89g x 1mol/46.07g) x (28.05g/1mol) = 4.80 g (L.R.) %3D 30 x 1.840g/mol = (55.2g x 1mol/98.08g) x (28.05/1mol) = 15.8 g %3D

Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter4: Chemical Reactions
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TOPIC: Preparation of Ethylene

Expound and explain the given answer to the question.

What is the theoretical yield of the given reaction?
CH,CH,OH + H,SO, > CH,=CH, + H,0
10ml ethanol (MM: 46.07g/mol); ethylene (MM: 28.05); 30mL sulfuric acid
10 x 0.789g/mol = (7.89g x 1mol/46.07g) x (28.05g/1mol) = 4.80 g (L.R.)
%3D
30 x 1.840g/mol = (55.2g x 1mol/98.08g) x (28.05/1mol) = 15.8 g
Transcribed Image Text:What is the theoretical yield of the given reaction? CH,CH,OH + H,SO, > CH,=CH, + H,0 10ml ethanol (MM: 46.07g/mol); ethylene (MM: 28.05); 30mL sulfuric acid 10 x 0.789g/mol = (7.89g x 1mol/46.07g) x (28.05g/1mol) = 4.80 g (L.R.) %3D 30 x 1.840g/mol = (55.2g x 1mol/98.08g) x (28.05/1mol) = 15.8 g
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