General, Organic and Biochemistry - Laboratory Manual3. a) How would you record the following volume measurement on a burette shown in thepicture using rules of significant figures?07.mLV=b) If the burette was used to dispense a certain amount of solution, and the new volumereading is shown in the picture below, what volume of the solution was dispensed? Userules of significantfigures and showyourwork!9FD11AHUA12/009/W0 1 #11mLVdispensed1Show work:DNHUO6110me

The shown reading is in between 8 to 9. It is further divide in to ten digits. The second decimal…

Answered: General, Organic and Biochemistry -…

Chemistry

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Chapter11: Properties Of Solutions

Section: Chapter Questions

Problem 109AE: Patients undergoing an upper gastrointestinal tract laboratory test are typically given an X-ray...

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Concentration of AR Stock Solution (ppmppm) 21.22 Unrounded Rounded Concentration of AR Stock Solution (μMμM) 42.7461 42.7
What is the concentration in units of grams of dye per liter of solution ,of the dilute dye solution that is produced as follows? transfer 19.53 ml of stick solution (6.10g/L) to a 200.0Ml volumetric flask and dilute to the 200 ml line with deionized water. Correct number of significant figs
Volume of an unknown used was 30 mL, Initial Buret volume was 0 and the Final Buret volume was 8.5 mL. What is the molarity of the unknown solution if the Net volume of NaOH being used was 8.5 mL and Millimoles (mmoles) NaOH reacted was 0.791? Then, what is the Mass (g) of Acetic Acid in unknown sample and thr average percent (%) Acetic Acid? (assume density = 1g/mL)
What's the differences between two questions? Q1) How much calcium would you ingest by drinking one 8 oz glass of your tap water? Show all calculations. -->Tap water 8Oz = 8 x 0.0296L = 0.2368L Hardness = 66.73ppm = 66.73mg/L CaCO3 1L has 66.73mg CaCO3 0.2368L has 66.73mg x 0.2368 = 15.8017mg MW of CaCO3 = 100g/mol MW of Ca = 40g/mol 100g CaCO3 has 40gf of Ca 15.8017mg CaCO3 has 40/100 x 15.8017mg Ca We would ingest 6.321mg of Ca. Q2) What percentage of the recommended daily dose of calcium (1,150 mg/day) does 1.0 L of your water provide? Show all calculations. --> 66.73mg/1150mg x 100 = 5.80% My Question) Why this calculation is wrong? I think this calculation is same with question 1. Isn't it? CaCO3 = 100g/mol, Ca = 40g/mol 100g CaCO3 has 40g Ca. 66.73 CaCO3 has 40/100 x 66.73mg Ca Ca = 26.70mg 26.70mg/1150mg x 100 = 2.32%
Stock iron(II) solution (200Ug mL-1 Fe) ferrous ammonium sulfate hexahydrate mass= 0.1437g, transfer it to a 100 ml beaker. add 15 ml approx of water and 15m1 'approx of dilute sulphuric acid (2M H2SO.). then transfer FeII to 100 ml flask makeup to the mark with water. calculate the moles of ferrous ammonium sulfate hexahydrate solution in unit ug/mL.
Complete the table by entering the molarity of B2- for each standard solution. Show an illustrative calculation for tube ‘A’. Use the dilution formula and express each result to one more digit than allowed by applying the rules of significant figures. Standard Volume of stock B2- solution taken, mL Molarity of dilute B2 Construct a graph of Absorbance vs. molarity of B2- in Excel using the data in the preceding table. Make certain to title the graph and include axes labels with proper units. Absorbance is dimensionless (has no unit). Add a linear trendline to the graph but do not set the y-intercept to zero Solid M2B is added to 25 mL of water, the resulting mixture is continually stirred for 1 hour. At this point, it is assumed that equilibrium (eqn 3) has been established. The mixture is transferred to a test tube, and the test tube is centrifuged to assure that any residual solid M2B is fully settled out. A portion of the supernatant in the test tube is carefully…
i have hard time geting it stright even after I do the experiment can u help me with the one pls Material ChemicalsSealed NO2 tubes, KSCN solution (0.002 M), acidified Fe(NO3)3 solution (0.2 M), KSCN crystals, Fe(NO3)3 crystals, KOH (concentrated (8 M)), distilled waterApparatus:Bunsen burner, ring stand, wire gauze, matches, thermometer, dropper, test tubes, glass stirring rod, beaker tongs Procedure Part A: Fill a 600 mL beaker to the 3/4 mark with water. Bring to a boil using a Bunsen burner. In another 600 mL beaker, fill to the 1/2 mark with water; add ice in order to lower the temperature to about 0°C. Note the room temperature. Observe the NO2 thoroughly at room temperature. Place the sealed NO2 tube in the cold bath. Note your observations. Remove the test tube from the cold bath. Let the test tube stand until it reaches room temperature. Note your observations. Place the test tube in the hot bath. Note your observations. Remove the test tube from the hot bath. Let the test…
Preparation of 100 ml 1.0 molar (1.0M) H2SO4 solution (specific gravity, 1.8 g/ml and purity, 98%). H2SO4 molecular weight is 98 grams.
If V = 125ml at 755 mm Hg, find V (ml) at 780 mm Hg (temp, n = count)
0.02 M NaOH reagent was standardized using 0.1000 g Potassium hydrogen phthalate (204.22 g/mol) and it required 25.8 mL to reach end point. Answer must be in 4 decimal places.
If you have 6.74 g of caffeine dissolved in 68.12 mL of water and the extraction coefficient between H2O and CH2Cl2 is 21.51. How many grams of caffeine will extract into the CH2Cl2 layer if you add 80.72 mL? Please provide your answers with two decimal places. need to do math for this one
Determine the distance traveled by the solvent if the solute travels 3.1 cm. The weight of the analyte measures 0.984 mg with an Rf value of 0.647. Note: Express answers up to TWO decimal places. Distance traveled by the solvent = cm

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