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What volume of a 13.0 mol·L−1 stock solution would you need to dilute to prepare 2.42 L of a 8.00 mol·L−1 solution?

What volume of a 13.0 mol·L−1 stock solution would you need to dilute to prepare 2.42 L of a 8.00 mol·L−1 solution?

Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter4: Chemical Reactions In Solution
Section: Chapter Questions
Problem 4.46QE
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What volume of a 13.0 mol·L−1 stock solution would you need to dilute to prepare 2.42 L of a 8.00 mol·L−1 solution?

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Let’s put the above values into the formula:

V1 = 8.00 mol.L-1 × 2.42 L13.0 mol.L-1V1 = 8.00 mol.L-1 × 2.42 L13.0 mol.L-1V1 = 8.00 × 2.42 L13.0V1 = 1.4892 LV1 = 1.49 L

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