Linear molecule-larger surface area enhanoes intermoleoular oontaot and inoreases dispersion foroe. n-Pentane (CH12) bp = 309.4 K Spherical molecule-emaller surface area diminishes intermolecular oontact and deoreases dispersion foroe. Neopentane (C;H12) bp = 282.7 K A Figure 11.6 Molecular shape affects
Linear molecule-larger surface area enhanoes intermoleoular oontaot and inoreases dispersion foroe. n-Pentane (CH12) bp = 309.4 K Spherical molecule-emaller surface area diminishes intermolecular oontact and deoreases dispersion foroe. Neopentane (C;H12) bp = 282.7 K A Figure 11.6 Molecular shape affects
Chapter7: Statistical Data Treatment And Evaluation
Section: Chapter Questions
Problem 7.9QAP
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Question
(a) Would you expect the viscosity of n-pentane,
CH3CH2CH2CH2CH3, to be larger or smaller than the viscosity
of n-hexane, CH3CH2CH2CH2CH2CH3? (b) Would
you expect the viscosity of neopentane, (CH3)4C, to be
smaller or larger than the viscosity of n-pentane? (See Figure
11.6 to see the shapes of these molecules.)
Transcribed Image Text:Linear molecule-larger
surface area enhanoes
intermoleoular oontaot and
inoreases dispersion foroe.
n-Pentane (CH12)
bp = 309.4 K
Spherical molecule-emaller
surface area diminishes
intermolecular oontact and
deoreases dispersion foroe.
Neopentane (C;H12)
bp = 282.7 K
A Figure 11.6 Molecular shape affects
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