Liquid oxygen was first prepared by heating potassium chlorate, KCIO3, in a closed vessel to obtain oxygen at high pressure. The oxygen was cooled until it liquefied. 2KCIO3 (s) → 2KCI(s) + 302 (g) If 165.0 g of potassium chlorate reacts in a 2.60-L vessel, which was initially evacuated, what pressure of oxygen will be attained when the temperature is finally cooled to 25°C? Use the preceding chemical equation, and ignore the volume of solid product. Pressure = atm O2
Liquid oxygen was first prepared by heating potassium chlorate, KCIO3, in a closed vessel to obtain oxygen at high pressure. The oxygen was cooled until it liquefied. 2KCIO3 (s) → 2KCI(s) + 302 (g) If 165.0 g of potassium chlorate reacts in a 2.60-L vessel, which was initially evacuated, what pressure of oxygen will be attained when the temperature is finally cooled to 25°C? Use the preceding chemical equation, and ignore the volume of solid product. Pressure = atm O2
General Chemistry - Standalone book (MindTap Course List)
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Chapter5: The Gaseous State
Section: Chapter Questions
Problem 5.117QP: Liquid oxygen was first prepared by heating potassium chlorate, KClO3, in a closed vessel to obtain...
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