I/*** Look for patterns like "zip" and "zap"* in the string -- length-3, starting with* 'z' and ending with 'p'. Return a string* where for all such words, the middle letter* is gone, so "zipXzap" yields "zpXzp".11* Examples:zipZap("zipXzap") -> "zpXzp"zipZap("zopzop") -> "zpzp"zipZap("zzzopzop") -> "zzzpzp"%3D* @param str the input string* @return a new string as described*/// TODO: Write method zipZap here...45 }

public static String zipZap(String s) { String res = ""; int i; for(i = 0; i < s.length() -…

/** * Look for patterns like "zip" and "zap" * in the string -- length-3, starting with * 'z' and ending with 'p'. Return a string * where for all such words, the middle letter * is gone, so "zipXzap" yields "zpXzp". * Examples: zipZap("zipXzap") -> "zpXzp" zipZap("zopzop") -> "zpzp" zipZap("zzzopzop") -> "zzzpzp" * @param str the input string * @return a new string as described */ // TODO: Write method zipZap here...

/** * Look for patterns like "zip" and "zap" * in the string -- length-3, starting with * 'z' and ending with 'p'. Return a string * where for all such words, the middle letter * is gone, so "zipXzap" yields "zpXzp". * Examples: zipZap("zipXzap") -> "zpXzp" zipZap("zopzop") -> "zpzp" zipZap("zzzopzop") -> "zzzpzp" * @param str the input string * @return a new string as described */ // TODO: Write method zipZap here...

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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def is_palindrome_string(string: str) -> bool:"""Given a string <string>, return whether this string is a palindrome string.for ANY CONTINUOUS SEGMENT OF ALPHABETICAL CHARACTERS. That means that "abc;def", has two words: "abc"and "def". The separating character does not have to be whitespace, andthere could be more than one separating character between two words.A simple example: given the string "test string test", there are threewords, "test", "string", and "test". The first letters of each word cometogether to form the string "tst". And since "tst" is a palindrome, thisfunction should return True for the input "test string test".Precondition: <string> will contain at least one word.""" " please code this in python and also add this code def is_palindrome(string: str) -> bool:string = string.replace(" ", "")return string.lower() == string[::-1].lower() and use is_palindrome in the main function "
def is_palindrome_string(string: str) -> bool:"""Given a string <string>, return whether this string is a palindrome string.for ANY CONTINUOUS SEGMENT OF ALPHABETICAL CHARACTERS. That means that "abc;def", has two words: "abc"and "def". The separating character does not have to be whitespace, andthere could be more than one separating character between two words.A simple example: given the string "test string test", there are threewords, "test", "string", and "test". The first letters of each word cometogether to form the string "tst". And since "tst" is a palindrome, thisfunction should return True for the input "test string test".Precondition: <string> will contain at least one word."""
int i cannot be changed with int pos I have to fill in the program that is missing in the middle by using what is already there in C++. Started with this but does not like it cout << "Enter passwdStr: "; getline(cin, passwdStr); while (passwdStr.find("qwerty") != string::npos) { passwdStr.replace(int i, 6, "mvhnkl"); i = passwdStr.find("qwerty"); }
Implement the GetNumOfWords() function. GetNumOfWords() has a constant string as a parameter and returns the number of words in the string. Hint: Words end when a space is reached except for the last word in a sentence. Call GetNumOfWords() in the PrintMenu() function.Ex: Number of words: 35
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def while_loops(string1: str, string2: str) -> str:""" Given two strings <string1> and <string2>, return a new string that contains letters from these two strings "interwoven" together, starting with the first character of <string1>. If the two strings are not of equal length, then start looping "backward-and-forwards" in the shorter string until you come to the end of the longer string. We ask that you use while loops and keep them simple and precise.>>> while_loops("abcde","12")'a1b2c1d2e1'>>> while_loops("ab","123")'a1b2a3'>>> while_loops("abcdfe","123")'a1b2c3d2f1e2'>>> while_loops("c","ab")'cacb'""" don't use any reverse or any other def do in on def while_loop, prove these doctests and write the code in python and don't add any import or any dictionaries or dictionary methods or any try-except statements
Q12,. A phrase is a palindrome if, after converting all uppercase letters into lowercase letters and removing all non-alphanumeric characters, it reads the same forward and backward. Alphanumeric characters include letters and numbers. Given a string s, return true if it is a palindrome, or false otherwise. Example 1: Input: s = "A man, a plan, a canal: Panama" Output: true Explanation: "amanaplanacanalpanama" is a palindrome. Example 2: Input: s = "race a car" Output: false Explanation: "raceacar" is not a palindrome..
Create a class NestedForPatternB. Use nested for-loops that display the following pattern:
def while_loops(string1: str, string2: str) -> str:""" Given two strings <string1> and <string2>, return a new string that contains letters from these two strings "interwoven" together, starting with the first character of <string1>. If the two strings are not of equal length, then start looping "backward-and-forwards" in the shorter string until you come to the end of the longer string.we ask that you used while loops and keep them simple and precise.>>> while_loops("abcde","12")'a1b2c1d2e1'>>> while_loops("ab","123")'a1b2a3'>>> while_loops("abcdfe","123")'a1b2c3d2f1e2'>>> while_loops("c","ab")'cacb'""" prove these doctests and write the code in python and don't add any import or any dictionaries or dictionary methods or any try-except statements
Question : Let s be a string of length 2 with characters from {0, 1, 2}, and define statements a, b, c, and d as follows: a = "the first character of s is 0” b = “the first character of s is 1” c = “the second character of s is 1” d = “the second character of s is 2”. Describe the set of all strings for which each of the following is true.? ----on picture
Read the input one line at a time and output the current line if and only if it is largerthan any other line read so far or strictly smaller than the previously outputted line. (Here,smaller is with respect to the usual order on Strings, as defined by String.compareTo()). you have to use arrylist and cant modify any code under public static void main(string[] args). example: input 138456792 output: 138492 import java.util.*; import java.io.BufferedReader; import java.io.FileReader; import java.io.FileWriter; import java.io.IOException; import java.io.InputStreamReader; import java.io.PrintWriter; import java.util.Stack; public class Part2 { /** * Your code goes here - see Part0 for an example * @param r the reader to read from * @param w the writer to write to * @throws IOException */ public static void doIt(BufferedReader r, PrintWriter w) throws IOException { /*ArrayList<String> arr = new ArrayList<>(); int count…
Implement function rotate that takes a string argument s and an integer argument n, and rotates the string s to the left by n times. For example, the code char s[] = "systems"; rotate(s, 3); will change s into "temssys", while the code char t[] = "abcd"; rotate(t, 1); will change t into "bcda". void rotate(char *w, int j)