Read the input one line at a time and output the current line if and only if it is larger than any other line read so far or strictly smaller than the previously outputted line. (Here, smaller is with respect to the usual order on Strings, as defined by String.compareTo()). you have to use arrylist and cant modify any code under public static void main(string[] args).  example: input 1 3 8 4 5 6 7 9 2 output: 1 3 8 4 9 2     import java.util.*; import java.io.BufferedReader; import java.io.FileReader; import java.io.FileWriter; import java.io.IOException; import java.io.InputStreamReader; import java.io.PrintWriter; import java.util.Stack; public class Part2 {         /**      * Your code goes here - see Part0 for an example      * @param r the reader to read from      * @param w the writer to write to      * @throws IOException      */     public static void doIt(BufferedReader r, PrintWriter w) throws IOException {         /*ArrayList arr = new ArrayList<>();         int count = 0;         String max = "0";         int len = 0;         for (String line = r.readLine(); line != null; line = r.readLine()) {                         arr.add(line);             if(arr.get(count).compareTo(max) > 0 ){                 max = arr.get(count);                 w.println(arr.get(count));             }             if(arr.get(count).length() > 1){                 if(arr.size()> 1){                     if(arr.get(count).length() >max.length()){                                             len = arr.get(count).length();                         max = arr.get(count);                         w.println(arr.get(count));                         System.out.println("1: " + arr.get(count));                     }                     if(arr.get(count).length() == arr.get(count - 1).length()){                         if(arr.get(count).length() >= len && arr.get(count).compareTo(max) > 0){                             max = arr.get(count);                             w.println(arr.get(count));                             System.out.println("2: " + arr.get(count));                         }                     }                     if(arr.get(count -1).compareTo(max) == 0 && arr.get(count).compareTo(arr.get(count -1)) < 0){                               w.println(arr.get(count));                         System.out.println("3: " + arr.get(count));                     }                 }             }             if(arr.size()> 1){                 if(arr.get(count).length() < 2){                     if(arr.get(count -1) == max && arr.get(count).compareTo(arr.get(count -1) )< 0){                                                 w.println(arr.get(count));                     System.out.println("4: " + arr.get(count));                     }                 }             }             count++;         }*/         //write your code here     }       /**      * The driver.  Open a BufferedReader and a PrintWriter, either from System.in      * and System.out or from filenames specified on the command line, then call doIt.      * @param args      */     public static void main(String[] args) {         try {             BufferedReader r;             PrintWriter w;             if (args.length == 0) {                 r = new BufferedReader(new InputStreamReader(System.in));                 w = new PrintWriter(System.out);             } else if (args.length == 1) {                 r = new BufferedReader(new FileReader(args[0]));                 w = new PrintWriter(System.out);                             } else {                 r = new BufferedReader(new FileReader(args[0]));                 w = new PrintWriter(new FileWriter(args[1]));             }             long start = System.nanoTime();             doIt(r, w);             w.flush();             long stop = System.nanoTime();             System.out.println("Execution time: " + 1e-9 * (stop-start));         } catch (IOException e) {             System.err.println(e);             System.exit(-1);         }     } }

In Java please

Generate a list of 10 random numbers with values between 1 and 20, and submit the first 10 numbers as an answer to this question. (Use any random number generator). For the purpose of using them in the next questions, call these numbers A, B, C, D, . . . J Convert Aπ/B into degrees. Find the result ofa. Degrees = (A × B × C) + 180 mod 180; this is the remainder after dividing (A × B × C) + 180 by 180 b. Convert Degrees into radians, and put the answer in π notation. Calculate the measurements of the acute angles of a right triangle whose sides measure A, B, C units. Build a matrix, M, of random numbers as follows: A B C D E F G H I What is MT? Find the inverse of M, showing the steps. What is the result of M * M−1? Let V = [A B C] and W = [ D E F]. In the textbook, the dot product V • W involves an angle, alpha (α). How do you calculate alpha for this example? Let V = [A B C]. Find the cross product V • V. What can you conclude from this…

Please help me fix this program. It is constantly saying I have duplicates of class main and many more Main. Java is below as well as my gui which is the photos (the gui is my problem) import java.util.*; public class Main { //Inputs a one character string and returns True if the character is a letter (i.e. a to z or A to Z). Returns false if it is not. A function to check that the password or encryption key is valid. public static boolean isALetter(char letter){ if( (letter >= 'a' && letter = 'A' && letter =-32767 && encryptKey