def while_loops(string1: str, string2: str) -> str: """ Given two strings and , return a new string that contains letters from these two strings "interwoven" together, starting with the first character of . If the two strings are not of equal length, then start looping "backward-and-forwards" in the shorter string until you come to the end of the longer string.we ask that you used while loops and keep them simple and precise. >>> while_loops("abcde","12") 'a1b2c1d2e1' >>> while_loops("ab","123") 'a1b2a3' >>> while_loops("abcdfe","123") 'a1b2c3d2f1e2' >>> while_loops("c","ab") 'cacb' """ prove these doctests and write the code in python and don't add any import or any dictionaries or dictionary methods or any try-except statements

Complete the rotate_text() function that takes 2 parameters, a string data and an integer n. If n is positive, then the function will shift all the characters in data forward by n positions, with characters at the end of the string being moved to the start of the string. If n is 0 then the text remains the same. For example: rotate_text('abcde', rotate_text('abcde', rotate_text('abcde', 1) would return the string 'eabcd' 3) would return the string 'cdeab' 5) would return the string 'abcde' rotate_text('abcde', 6) would return the string 'eabcd' ... and so on. If n is negative, then the function will shift the characters in data backward by n positions, with characters at the start of the string being moved to the end of the string. For example: rotate text('abcde', -1) would return the string 'bcdea'

Using c++ Contact list: Binary Search   A contact list is a place where you can store a specific contact with other associated information such as a phone number, email address, birthday, etc. Write a program that first takes as input an integer N that represents the number of word pairs in the list to follow. Word pairs consist of a name and a phone number (both strings). That list is followed by a name, and your program should output the phone number associated with that name. Define and call the following function. The return value of FindContact is the index of the contact with the provided contact name. If the name is not found, the function should return -1 This function should use binary search. Modify the algorithm to output the count of how many comparisons using == with the contactName were performed during the search, before it returns the index (or -1). int FindContact(ContactInfo contacts[], int size, string contactName) Ex: If the input is: 3 Frank 867-5309 Joe…

exercise5.py 1 Your code goes here... Guide Collapse Strings -> Coding Exercises - Strings Exercise 5 Exercise 5 Problem Write a program that captures input from the user. Then, swap the letters two at a time in the string. The first two characters change places, the third and fourth characters change places, etc. Assume that the user will only input strings with an even number of characters. Important, do not put a prompt when asking for user input. Just use input(). Adding a prompt will cause your program to not pass the tests. Expected Output • If the user inputs home, then the output is ohem . If the user inputs cars then the output is acer Code Visualizer TRY IT Reminder, do not put a prompt when collecting user input. Just use input() Check It! (1 left) TTT

The function count_contains_og in python takes a list of strings and returns how many strings in the list contain 'og' / 'OG' / 'oG' / 'Og' (check for 'og', ignoring case). Hint: Use the sequence membership operator in to help you check for 'og' in the individual strings. Create a lower-cased version of the string (lower), then use the in operator. For example: Test Result str_list = ['cat', 'dog', 'FROG', 'monkey'] print(count_contains_og(str_list)) 2 strlist = ["X", "x"] print(count_contains_og(strlist)) 0 list_of_one_og = ["Doggie"] print(count_contains_og(list_of_one_og)) 1

Thank you! but for nextTweet and removeTweet. can u rewrite base on the specs:  public String nextTweet() Returns the next tweet from the tweet list. If all the tweets in the list are exhausted, cycle around to the start of the list. For example, the following code snippet should produce the output in the comments. Suppose that tweets stores a list of Tweets ["A tweet about something controversial", "Remember to vote!", "Look at this meme :O"]. TweetBotbot=newTweetBot(tweets); System.out.println(bot.nextTweet()); // A tweet about something controversial System.out.println(bot.nextTweet()); // Remember to vote! System.out.println(bot.nextTweet()); // Look at this meme :O System.out.println(bot.nextTweet()); // A tweet about something controversial Think about how to get the next tweet from the list of tweets, and how you can cycle around to the start once you've gone through all the tweets! One Special Case! As you're working on your TweetBot and testing your implementation,…

Use a while loop function instead of a for loop sing python