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- If one mixes 50cm³ of EtOH and 50cm³ of H2O at room temperature; will the total volume of the solution be 100.0 cm³? Justify answer with appropriate calculations and explanations1.Determine the mass of sodium chloride required to prepare 400 ml of a Mueller-Hinton broth supplemented with 5.5% (wt/vol) sodium chloride solution. [Mwt NaCl = 58.44 g/mol] 2.Determine the mass of Fe(OH)3 that is required to prepare 350 ml of a 5N Fe(OH)3 solution. [Mwt Fe(OH)3 = 106.867g/mole]A 100-liter empty jar was spiked with 20 mg of TCE (C2HCl3) under room temperature condition. The jar was then closed tightly. What is the concentration (in atm.) of TCE in the air at 25 C? (TCE: MW: 131.4 g/mol; TCE solubility in water (Cs) = 1100 mg/L; Pv (pure liquid at 25oC) = 10^-1.01 atm. KH = 10^1.03 L atm mol-1; KOW = 102.42). if the jar was half filled with water and half filled with air, what were the concentrations of TCE in both air and water at 25C?
- A sample containing chlorophenol, C6H4ClOH, was analysed by gravimetric analysis. A 0.783-g of this sample goes through a chemical process allowing the chlorine in the chlorophenol to precipitate as silver chloride, weighing 0.271 g. Calculate the % (wt/wt) of the chlorophenol in the sample, assuming that chlorophenol is the only source of chlorine in the sample. Provide your answer to two decimal places and without units. Avoid using scientific notation.In an experiment, 0.500 grams of sodium bicarbonate were added to an evaporating dish and an excess of 6.0 M hydrochloric acid was added. The bicarbonate bubbled with the addition of the aqueous HCl. The evaporating dish was gently swirled until the bubbling stopped. The evaporating dish was placed on a hot plate and heated carefully to dryness so that it was completely dry and at constant mass. The amount of sodium chloride obtained from the evaporating dish was 0.114 g. The reaction is given below. NaHCO3 (s) + HCl (aq) ---> NaCl (s) + CO2 (g) + H2O (l) Question: Is the reaction balanced?In an experiment, 0.500 grams of sodium bicarbonate were added to an evaporating dish and an excess of 6.0 M hydrochloric acid was added. The bicarbonate bubbled with the addition of the aqueous HCl. The evaporating dish was gently swirled until the bubbling stopped. The evaporating dish was placed on a hot plate and heated carefully to dryness so that it was completely dry and at constant mass. The amount of sodium chloride obtained from the evaporating dish was 0.114 g. The reaction is given below. NaHCO3 (s) + HCl (aq) ---> NaCl (s) + CO2 (g) + H2O (l) Is the reaction balanced? What was in the bubbles? What were the actual, theoretical, and percent yields of sodium chloride (NaCl)? You must show your work to receive credit.
- In an experiment, 0.500 grams of sodium bicarbonate were added to an evaporating dish and an excess of 6.0 M hydrochloric acid was added. The bicarbonate bubbled with the addition of the aqueous HCl. The evaporating dish was gently swirled until the bubbling stopped. The evaporating dish was placed on a hot plate and heated carefully to dryness so that it was completely dry and at constant mass. The amount of sodium chloride obtained from the evaporating dish was 0.114 g. The reaction is given below. NaHCO3 (s) + HCl (aq) ---> NaCl (s) + CO2 (g) + H2O (l) What were the actual, theoretical, and percent yields of sodium chloride (NaCl)?In an experiment, 0.500 grams of sodium bicarbonate were added to an evaporating dish and an excess of 6.0 M hydrochloric acid was added. The bicarbonate bubbled with the addition of the aqueous HCl. The evaporating dish was gently swirled until the bubbling stopped. The evaporating dish was placed on a hot plate and heated carefully to dryness so that it was completely dry and at constant mass. The amount of sodium chloride obtained from the evaporating dish was 0.114 g. The reaction is given below. NaHCO3 (s) + HCl (aq) ---> NaCl (s) + CO2 (g) + H2O (l) Question: What were the actual, theoretical, and percent yields of sodium chloride (NaCl)?A 15.0% by weight solution was prepared using 90.0g of KCl and the resulting density of the solution is 1.101g/mL. (MW KCl 74g/n). volume of solution(mL)? milliosmole of solute? %w/v? weight of solvent(g? N?