[N2][02][N2][02]?N2(g) + O2(g) = N2O2(g)K =[N] [0]?[N202][N202][N2][02]2NO2(g) = N2(g) + 202(g)K =[N2][02][NO]?[NO]?[N]?[0]?N2(g) + 202(g) = 2NO2(g)K =[N202][N2][02][N202][N] [0]?N2(g) + O2(g) = 2NO(g)K =(N] [0]?[NO]2[NO,]2[N]?[02]?N2O2(g) = N2(g) + O2(g)K =ResetZoom Match each chemical equation below with the correct equilibrium constant expression.[N] [02]?[NO,1?Equilibrium ConstantExpressionChemical Equation[N2][02]?[NO2]?2NO(g) = N2(g) + O2(g)K =[NO]?[N2][02][NO,]?[N>][02]?N2(g) + O2(g) = N,O2(g)K =[N]°[0]?[N202][N202][N2][O2]2NO2(g) = N2(g) + 202(g)K ={N2][O2][NO]?[NO]?[N]?[0]?N2(g) + 202(g) =2NO2(g)K =[N202][N2][02][N202][N]?[0]?< Prev6 of 10Next >Rain to stop

Equilibrium constant (K) is the ratio of product of concentration of products raised to their…

Answered: Match each chemical equation below with…

Science

Chemistry

Match each chemical equation below with the correct equilibrium constant expression.

World of Chemistry, 3rd edition

3rd Edition

ISBN:9781133109655

Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste

Chapter17: Equilibrium

Section: Chapter Questions

Problem 17A

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Question

[N2][02]
[N2][02]?
N2(g) + O2(g) = N2O2(g)
K =
[N] [0]?
[N202]
[N202]
[N2][02]
2NO2(g) = N2(g) + 202(g)
K =
[N2][02]
[NO]?
[NO]?
[N]?[0]?
N2(g) + 202(g) = 2NO2(g)
K =
[N202]
[N2][02]
[N202]
[N] [0]?
N2(g) + O2(g) = 2NO(g)
K =
(N] [0]?
[NO]2
[NO,]2
[N]?[02]?
N2O2(g) = N2(g) + O2(g)
K =
Reset
Zoom

Match each chemical equation below with the correct equilibrium constant expression.
[N] [02]?
[NO,1?
Equilibrium Constant
Expression
Chemical Equation
[N2][02]?
[NO2]?
2NO(g) = N2(g) + O2(g)
K =
[NO]?
[N2][02]
[NO,]?
[N>][02]?
N2(g) + O2(g) = N,O2(g)
K =
[N]°[0]?
[N202]
[N202]
[N2][O2]
2NO2(g) = N2(g) + 202(g)
K =
{N2][O2]
[NO]?
[NO]?
[N]?[0]?
N2(g) + 202(g) =
2NO2(g)
K =
[N202]
[N2][02]
[N202]
[N]?[0]?
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