Methane and hydrogen sulfide react to form hydrogen and carbon disulfide, like this: CH4(g)+2H,S(g)→ 4H2(g)+CS,(g) Use this chemical equation to answer the questions in the table below. Suppose 225. mmol of CH, and O None. 4 450. mmol of H, S are added to an O Some, but less than 225. mmol. empty flask. How much CH, will be O 225. mmol. 4 in the flask at equilibrium? O More than 225. mmol. Suppose 250. mmol of H, and O None. 62.5 mmol of CS, are added to an O Some, but less than 62.5 mmol. O 62.5 mmol. empty flask. How much CH, will be 4 in the flask at equilibrium? O More than 62.5 mmol.

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Chapter4: Stoichiometry
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Methane and hydrogen sulfide react to form hydrogen and carbon disulfide, like this:
CH4(g)+2H,S(g)→ 4H2(g)+CS,(g)
Use this chemical equation to answer the questions in the table below.
Suppose 225. mmol of CH, and
O None.
4
450. mmol of H, S are added to an
O Some, but less than 225. mmol.
empty flask. How much CH, will be
O 225. mmol.
4
in the flask at equilibrium?
O More than 225. mmol.
Suppose 250. mmol of H, and
O None.
62.5 mmol of CS, are added to an
O Some, but less than 62.5 mmol.
O 62.5 mmol.
empty flask. How much CH, will be
4
in the flask at equilibrium?
O More than 62.5 mmol.
Transcribed Image Text:Methane and hydrogen sulfide react to form hydrogen and carbon disulfide, like this: CH4(g)+2H,S(g)→ 4H2(g)+CS,(g) Use this chemical equation to answer the questions in the table below. Suppose 225. mmol of CH, and O None. 4 450. mmol of H, S are added to an O Some, but less than 225. mmol. empty flask. How much CH, will be O 225. mmol. 4 in the flask at equilibrium? O More than 225. mmol. Suppose 250. mmol of H, and O None. 62.5 mmol of CS, are added to an O Some, but less than 62.5 mmol. O 62.5 mmol. empty flask. How much CH, will be 4 in the flask at equilibrium? O More than 62.5 mmol.
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