Methanol (CH4O) is converted to bromomethane (CH3Br) as follows: CH4O + HBr → CH3Br + H2O If 12.23 g of bromomethane are produced when 5.00 g of methanol is reacted with excess HBr, what is the percentage yield?

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Problem 3.98QP: Methyl salicylate (oil of wintergreen) is prepared by heating salicylic acid, C7H6O3, with methanol,...
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Methanol (CH4O) is converted to bromomethane (CH3Br) as follows:


CH4O + HBr → CH3Br + H2O


If 12.23 g of bromomethane are produced when 5.00 g of methanol is reacted with excess HBr, what is the percentage yield?

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