mixture of Oxygen and Chlorine gases contain twice as much Oxygen (by mass - in grams) as Chlorine   (2xO2g= Cl2g) If the total pressure of the mixture is 565mmHg, then what is the partial pressure of chlorine ?   Using (from Ideal Gas law - Dalton) Partial Pressure

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Chapter5: Gases
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A mixture of Oxygen and Chlorine gases contain twice as much Oxygen (by mass - in grams) as Chlorine   (2xO2g= Cl2g)

If the total pressure of the mixture is 565mmHg, then what is the partial pressure of chlorine ?

 

Using (from Ideal Gas law - Dalton) Partial Pressure

Partial Pressure (?)

Moles of Chlorine (?)  / (divided) by Total Moles O2+Cl2

or written   nA / n(Total Pressure)

 

I've tried to determine what multiple of Oxygen, in grams - by atomic mass, will give me 1/2 the weight of Chlorine - in order to determine Mole (mol) Count for each DIATOMIC.  

I'm not frustrated, but i'm a little tired of going through this, for 2 hours,

I have looked at - similar formula - variations, but this is the challenge.

 

 

thanks

 

9. A mixture of oxygen and chlorine gases contains twice as much oxygen (by mass)
as chlorine. If the total pressure of the mixture is 565 mmHg, then what is the partial
pressure of chlorine?
104 mmHg
Transcribed Image Text:9. A mixture of oxygen and chlorine gases contains twice as much oxygen (by mass) as chlorine. If the total pressure of the mixture is 565 mmHg, then what is the partial pressure of chlorine? 104 mmHg
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