Molarity: 0.148 M Na2S2O3 Data for Unknown Sample Trial 1 Trial 2 Mass of Sample 0.081 g 0.083 g Volume of Na2S2O3 ----------------- ------------------- Final Buret Reading 0.78 mL 0.84 mL Initial Buret Reading 0.07 mL 0.10 mL Net Volume of Na2S2O3 _____mL ______mL Calculation of Percentage NaOCl -------------- ------------- Moles of Na2S2O3 used _______mol _______mol Moles of NaOCl reacted _______mol _______mol Mass of NaOCl in sample _______g _______g Percentage by weight NaOCl (g NaOCl/g sample) X 100% _______% _______%

Molarity: 0.148 M Na2S2O3 Data for Unknown Sample Trial 1 Trial 2 Mass of Sample 0.081 g 0.083 g Volume of Na2S2O3 ----------------- ------------------- Final Buret Reading 0.78 mL 0.84 mL Initial Buret Reading 0.07 mL 0.10 mL Net Volume of Na2S2O3 _mL mL Calculation of Percentage NaOCl -------------- ------------- Moles of Na2S2O3 used _mol _mol Moles of NaOCl reacted _mol _mol Mass of NaOCl in sample _g _g Percentage by weight NaOCl (g NaOCl/g sample) X 100% _% ___%

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter13: Titrations In Analytical Chemistry

Section: Chapter Questions

Problem 13.4QAP

See similar textbooks

Similar questions

How many milliliters of a stock solution of 7.00 MM HNO3HNO3 would you have to use to prepare 0.170 LL of 0.550 MM HNO3HNO3? V= mL If you dilute 16.0 mLmL of the stock solution to a final volume of 0.350 LL , what will be the concentration of the diluted solution? M= M
Please help me find weight percentage of the unknown solution, Thank you in advance Data attached below: Data of unknown NaCl solution (by weight) weight of weighing bottle and solution: 34.91g weight of weighing bottle: 23.91g weight of the solution: 11.00g Initial buret reading 33.28ml Final buret reading: 43.26ml The volume of the solution; 9.98 ml The density of solution: 1.10 Weight % of unknow solution: ?
2. In Avogadro’s Number lab, we used oleic acid to create a monolayer on the surface of water. The oleic acid solution was prepared by dissolving oleic acid in ethanol and it has a concentration of 0.50% by volume. The following parameters of oleic acid will be helpful to solve this question: Molar mass: 282.47 g/mol Density = 0.895 g/mL A) What’s the mass of oleic acid in 1.00 mL of this oleic acid solution? B) How many oleic acid molecules are there in 1.00 mL of this oleic acid solution?
By pipet, 5.00 mLmL of a 0.823 MM stock solution of potassium permanganate (KMnO4) was transferred to a 50.00-mL volumetric flask and diluted to the calibration mark. Determine the molarity of the resulting solution.
What is the correct volume of 2.5 M PhMgBr in THF is needed to completely react with 1.5 mL of methyl benzoate? You do not need to consider an excess and should calculate (and choose) the minimum amount as required by the reaction stoichiometry). Enter your answer to one decimal place WITH the proper unit of measurement.
A 19.51 ݃ sample of impure methylamine, which contains 72.58% (by mass) of CH3NH2 , isreacted with 30.81 ݃ of pure oxygen gas:4CHଷNHଶ(g) + 9Oଶ(g) ⟶ 4COଶ(g) + 10HଶO(ℓ) + 2Nଶ(g) In another experiment, this impure methylamine was used as follows: An unknown mass of the impure compound is dissolved in enough water to make 500.0 ݉ܮof solution. 20 ݉ܮ of this solution was transferred by pipette to a clean 250 mL volumetric flask andmade up to the mark. The molarity of the CH3NH2 in the final solution was determined to be 0.103 M.Determine the mass of CH3NH2 present in the original amount of impure compound used tomake this solution.
KHP (aq)+NaOH (aq)-->NaKHP (aq)+H2O(l) Trial Vi (mL) Vf (mL) 1 36.19 48.56 2 3 A student masses out 1.096 grams of KHP, which is dissolved in 25.00 mL of DI water. This KHP solution is titrated with NaOH, as shown in the equation above. Calculate the molarity of the NaOH solution.
A solution is prepared by dissolving 155.0 mL of methanol (CH3OH, density = 0.791 g/mL) in 250 mL of water (density 1.00 g/mL) to give a final solution volume of 350.0 mL. Calculate the (a) molarity of the solution, (b) %wt/wt, (c) %wt/vol, (d) %vol/vol
and Employees CH STATE GE 90 ENDULERSE IS FOREVER "ON-Tame Name Jodi Rayal Molarity = wt. x1000 3. Calculate the massof Potassium hydrogen phthalate (KHP) to prepare a 250.0 mL solution of 0.1000 M KHP solution. Mol ut. x Voluse the 2500×1000 204.22250 mass Initial Buret Reading Final Buret Reading Vol NaOH Added Moles of NaOH Moles of HCI Volume of unknown HCI solution Concentration of HCI Average concentration of HCI of KHP = 5.11g 4. Complete the table below for the following neutralization reaction of an unknown concentration of hydrochloric acid with 0.100 M sodium hydroxide: Mu spate solution Trial 1 0 11.15 го data and calculate the concentration 15 Trial 2 11.15 22.15 Trial 3 22.15 33.25 abyh 067 LANDINUKASHU TROWTHCENTISSATE ARAD Ma That par މއކނި REMURNAR MISAMARALISERDRY Tile
How many grams of GaAs04 are required to prepare 2800 mL. of dissolution 0.035 N. ?
Calculate the mass of CO2formed if 150 mL of 0.5 M C4H10reacts with excess O2
Mass of vial + cap + isopentyl alcohol: 28.999g Mass of vial + cap: 24.825 Mass of isopentyl alcohol used (g) ? Moles of isopentyl alcohol used (mol) ? Volume of acetic acid used: 7.00mL Mass of acetic acid used (g) (d = 1.05 g/mL) ? Moles of acetic acid used (mol) ?

SEE MORE QUESTIONS

Recommended textbooks for you

Fundamentals Of Analytical Chemistry

Chemistry

ISBN:

9781285640686

Author:

Skoog

Publisher:

Cengage

Appl Of Ms Excel In Analytical Chemistry

Chemistry

ISBN:

9781285686691

Author:

Crouch

Publisher:

Cengage

Fundamentals Of Analytical Chemistry

Chemistry

ISBN:

9781285640686

Author:

Skoog

Publisher:

Cengage

Appl Of Ms Excel In Analytical Chemistry

Chemistry

ISBN:

9781285686691

Author:

Crouch

Publisher:

Cengage

SEE MORE TEXTBOOKS

GET THE APP

About FAQ Academic Integrity Sitemap Document Sitemap

Contact Bartleby Contact Research (Essays)High School Textbooks Literature Guides Concept Explainers by Subject Essay Help Mobile App

GET THE APP

Privacy

Your CA Privacy Rights

Your NV Privacy Rights

About Ads

Manage My Data

bartleby, a Learneo, Inc. business

Data for Unknown Sample	Trial 1	Trial 2
Mass of Sample	0.081 g	0.083 g
Volume of Na₂S₂O₃	-----------------	-------------------
Final Buret Reading	0.78 mL	0.84 mL
Initial Buret Reading	0.07 mL	0.10 mL
Net Volume of Na₂S₂O₃	_____mL	______mL
Calculation of Percentage NaOCl	--------------	-------------
Moles of Na₂S₂O₃ used	_______mol	_______mol
Moles of NaOCl reacted	_______mol	_______mol
Mass of NaOCl in sample	_______g	_______g
Percentage by weight NaOCl (g NaOCl/g sample) X 100%	_______%	_______%