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A local company sent you their green alternative for window cleaner to be tested for percent (w/v) acetic acid content. For your experiment, you first standardized your NaOH titrant with 0.8053 g of (99.80 % purity) KHP. You used 40.60 mL of NaOH for your standardization. After that you then analyzed a 10.00 mL sample and found that you needed 43.20 mL NaOH to reach the end point.
Summary of results:
Standardization |
Sample analysis |
||
KHP Weight (g) |
0.8053 g |
Volume of sample |
50.00 mL |
Purity |
99.80% |
NaOH (mL) used |
33.20 mL |
NaOH (mL) used |
40.60 mL |
|
|
Determine the following:
- Molarity of NaOH
- % (w/v) acetic acid
Step by step
Solved in 2 steps with 2 images
- A commercial vinegar was analyzed by titration to determine the percent acetic acid. Briefly, 10.00 mL of vinegar sample was diluted to 100. mL solution in a volumetric flask. A 25.00 mL aliquot from the diluted vinegar required 25.55 mL of 0.1005 M sodium hydroxide to reach the phenolphthalein endpoint From this experiment which is the standard solution used in titration? CH3COOH NaOH NaCH3COO C20H14O4A double indicator analysis of a soda ash sample was performed. The student weighed 0.4375 g of the soda ash sample and dissolved it to make 100.0 mL solution. The students then took a 25 mL aliquot of the sample solution, then added 25 mL H2O and performed double indicator titration. The phenolphthalein endpoint required 10.27 mL 0.04027 M HCl titrant. The sample was further titrated using Methyl Orange and took a total of 15.97 mL of the titrant to reach the endpoint. Given that the molar weight of Na2CO3 - 105.99 g/mol, NaHCO3 = 84.007 g/mol, and NaOH - 39.997 g/mol answer the following: a. What are the components of the soda ash sample? (The constituents of the sample came from Na2CO3, NaHCO3, and NaOH). b. What are the moles of each component in the titrated 25 mL aliquot? c. What is the percent composition in (% w/w) of each component in the soda ash sample?Oxalic acid dihydrate (H2C2O4 2H2O) can be used to standardize NaOH solution through acid-base titration. To determine the molarity of an unknown NaOH solution, a student weighed out 0.56 g of solid oxalic acid dihydrate and dissolved the solid in 32.8 mL of DI water. The resulting solution was used in a titration with the unknown NaOH solution (3 drops of phenolphthalein was used as an indicator). The balance chemical equation is given below. If the student used 21.21 mL of the unknown NaOH solution in the titration, what is the molarity of the NaOH solution? Keep the correct number of significant figures. H2C2O4 (aq) + 2NaOH (aq) --> Na2C2O4 (aq) + 2H2O (l)
- Oxalic acid dihydrate (H2C2O4 2H2O) can be used to standardize NaOH solution through acid-base titration. To determine the molarity of an unknown NaOH solution, a student weighed out 0.56 g of solid oxalic acid dihydrate and dissolved the solid in 32.8 mL of DI water. The resulting solution was used in a titration with the unknown NaOH solution (3 drops of phenolphthalein was used as an indicator). The balanced chemical equation is given below. If the student used 25.71 mL of the unknown NaOH solution in the titration, what is the molarity of the NaOH solution? Keep the correct number of significant figures. H2C2O4 (aq) + 2NaOH (aq) --> Na2C2O4 (aq) + 2H2O (l)A student performed three H2SO4 titrations in Part 2 using their 0.1048 M NaOH solution which they previously standardized in Part 1. They reported the following measurements: Determination #1 Determination #2 Determination #3 Final NaOH Burette Reading 37.65 mL 28.35 mL 26.23 mL Initial NaOH Burette Reading 12.80 mL 4.05 mL 1.73 mL How many moles of NaOH did they use in their first titration? Report your answer to the correct number of significant figures and only report the numerical value (no units).Please explain and show calculations on how to do it. A student was given a white powdered solid unknown sample mixture made-up of sodium carbonate and sodium hydroxide. He took 0.3721 g of dissolved in 250.0 mL distilled water. In each trial he took 50.00 mL of unknown sample solution and conducted double titration as shown in the videos against 0.1000 M HCl. He did 5 trials and his results are given below: Trial V1 (mL) V2 (mL) 1 10.00 2.00 2 3 4 5 Calculate % NaOH and % Na2CO3 for trial#1.
- Normality is same as Molarity for sodium hydroxide and normal = molar (for NaOH) Normality of sodium hydroxide = 0.10395N (normal) or Molarity of NaOH = 0.10395M (molar) Volume of NaOH consumed during the titration = 21.87 mL Mol wt of Naproxen = 230.26 g/mol Weight of Naproxen ds (i.e., sample) = 0.534g Calculate the % Purity (dried-basis) of Naproxen ds, given that the LOD results for Naproxen = 1.0% a 97.0 b 98.0 c 98.5 d 99.0 e 99.5 f none of the other answers.Part 1: Preparation of the Primary Citric Acid Standard Mass of Citric Acid: 4.05 g Volume of Citric Acid Solution: 7.5 (at the equivalence point) Moles of Citric Acid: 0211 mol (Molar Mass = 192.0 g/mol) Molarity of Citric Acid Solution: 0.2813 help me with part Part 2: Titration of the Sodium Hydroxide Solution Volume of Citric Acid at the Equivalence Point _____________ Moles of Citric Acid at the Equivalence Point _______________ Moles of NaOH at the Equivalence Point __________________ 3 NaOH + H3C6H5O7 à Na3C6H5O7 + 3 H2O Volume of NaOH _______________________________ 5. Calculated Molarity of NaOH _______________________Determine the Concentration of Ethanoic Acid in Vinegar Equipment / Apparatus: 250-mL conical flasks Clamp Burette Graduated cylinder Pipette Reagents / Materials: Vinegar Phenolphthalein indicator 0.2 M NaOH (standardized) Calculation: Molarity (M) of ethanoic acid The average measured volume of the NaOH from titration: Average volume of NaOH used = (21.5ml + 21.5ml + 21.6ml) / 3 =21.5ml No of mole of NaOH = Concentration of NaOH (0.2M) × Average volume of NaOH used When an acid is completely neutralized: No of moles of CH3COOH = No of moles of NaOH Using the moles of CH3COOH, the molarity of ethanoic acid in the 5.0-mL sample of vinegar is calculated: Molarity (M) CH3COOH = moles CH3COOH / volume of vinegar (0.005 dm3). Calculation: Mass / Volume Percent (m/v) of ethanoic acid To calculate the percent (m/v) of CH3COOH in vinegar, we convert the moles of ethanoic acid to grams using the molar mass of ethanoic acid, 60.1 g/mole. Mass of CH3COOH =…
- A chemistry student needs to standardize a fresh solution of sodium hydroxide. She carefully weighs out 303 mg of oxalic acid, a diprotic acid that can be purchased inexpensively in high purity, and dissolves it in 250mL of distilled water. The student then titrates the oxalic acid solution with her sodium hydroxide solution. When the titration reaches the equivalence point, the student finds she has used 104.5 mL of sodium hydroxidesolution. Calculate the molarity of the student's sodium hydroxide solution. Round your answer to 3 significant digits.A 0.15mL of phenolphthalein indicator was dropped to 10.00mL of an unknown acid. Then, 52.00mL from the 100mL of 10M NaOH Solution was placed in a 50mL burette. A titration experiment was done using the 10.15mL unknown acid with phenolphthalein indicator as analyte and the 52mL of NaOH as titrant. The solution turned pink when the final volume of the analyte was 10.68mL and the final reading in the burette was 51.47mL. What is the concentration of the unknown acid?A student performed three H2SO4 titrations in Part 2 using their 0.1276 M NaOH solution which they previously standardized in Part 1. They reported the following measurements: Determination #1 Determination #2 Determination #3 Final NaOH Burette Reading 20.72 mL 41.54 mL 21.59 mL Initial NaOH Burette Reading 0.12 mL 20.72 mL 0.83 mL What was the total number of moles of H2SO4 in their second titration? Report your answer to the correct number of significant figures and only report the numerical value (no units).