Treatment of Data: 17) mole amount of CaCO3 1 8) Theoretical Yield (g) of CaCO3 19) actual yield of CaCO320) Percent Yield (% ) ClipboardFontAlignmentNumberG20frACDEFHK1 1Volume of Na2CO3, mL15.782 2 Molarity of Na2CO3, mol/L1.1334 4Volume of CaCl2, mL10.905 5 Molarity of CaCl2, mol/L1.276.78 8Mass of the filter paper, g1.009 9Mass of the watch glass, g2.1710 10 Mass of the filter paper + watch glass + wet product, g11.3811 11 Mass of the filter paper + watch glass + dry product, g8.881212

We have to find the moles of CaCO3 produced

Answered: mole amount of CaCO3 1 8)…

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mole amount of CaCO3 1 8) Theoretical Yield (g) of CaCO3 19) actual yield of CaCO3 20) Percent Yield (% )

Chemistry

9th Edition

ISBN:9781133611097

Author:Steven S. Zumdahl

Publisher:Steven S. Zumdahl

Chapter11: Properties Of Solutions

Section: Chapter Questions

Problem 109AE: Patients undergoing an upper gastrointestinal tract laboratory test are typically given an X-ray...

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Concept explainers

Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

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Treatment of Data:

17) mole amount of CaCO3

1 8) Theoretical Yield (g) of CaCO3

19) actual yield of CaCO3

20) Percent Yield (% )

Clipboard
Font
Alignment
Number
G20
fr
A
C
D
E
F
H
K
1 1
Volume of Na2CO3, mL
15.78
2 2 Molarity of Na2CO3, mol/L
1.13
3
4 4
Volume of CaCl2, mL
10.90
5 5 Molarity of CaCl2, mol/L
1.27
6.
7
8 8
Mass of the filter paper, g
1.00
9 9
Mass of the watch glass, g
2.17
10 10 Mass of the filter paper + watch glass + wet product, g
11.38
11 11 Mass of the filter paper + watch glass + dry product, g
8.88
12
12

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