please Which of the following statements is true aboutsimple harmonic motion?The angular frequency increases as the massincreases.The amplitude is a function of time.The spring constant has a unit of kilogram persecond.The period increases as the mass increases.

Simple Harmonic Motion or SHM is defined as a motion in which the restoring force is directly…

Answered: mple harmonic motion? The angular…

Science

Physics

mple harmonic motion? The angular frequency increases as the ma increases.

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter12: Oscillatory Motion

Section: Chapter Questions

Problem 3CQ

See similar textbooks

Related questions

Q: The blade of a fan is 0.20 m long and makes 20 revolutions/seconds a) What is the period of the…

A: A) Given Frequency f = 20 rev /sec Time period T = 1/f So T = 1/20 T = 0.05 sec

Q: Astronauts on a distant planet set up a simple pendulum that has an angular frequency of .455 on…

Q: A pendulum is swinging back and forth. The angele 0 that the pendulum's string makes with e vertical…

A: We will first differentiate angular displacement to get angular velocity following maximizing…

Q: A block – spring system consists of a spring with constant k = 425 N/m attached to a 2.00 - kg block…

A: 10.Step 1It is given that

Q: A particle executes simple harmonic motion with an amplitude of 3.00 cm. At what position does its…

A: Given Data : The amplitude of the simple harmonic motion is given as A = 3cm

Q: A simple harmonic motion setup yields the following for position: x = A sin(wt). What is the…

A: Given data: Position function of the simple harmonic motion x = Asin(ωt) Required: Acceleration (a)…

Q: 5b. A box attached to a spring goes up and down from rest with a displacement of 0.25m. If the…

A: solution of above question given in below step.

Q: The fan blades on a jet engine make one thousand revolutions in a time of 25.7 ms. What is the…

A: The expression for the angular frequency of the blades is,

Q: The acceleration of a simple harmonic oscillator is given by a = – (20.5 m/s?) cos (4.23t). What is…

A: given a=-20.5 cos (4.23t)

Q: You rev your car's engine to 3100 rpm (rev/min). 1) What is the period of the engine? T=(?)s 2)What…

Q: Q1. In figures a and b find the angular frequency for the simple harmonics leire eel S4

Q: A block is tied to a spring and is oscillating with an amplitude of A = 17 cm. The angular frequency…

A: amplitude(A)=17cm=0.17m angular frequency(ω)=4 rad/sec maximum acceleration of block is given by…

Q: A spring-mass system consists of a mass m = 2.0 kg and spring with spring constant k = 290 N/ %3D…

A: Given Mass m = 2.0 kg spring constant k = 290 N/m We have to find out angular frequency

Q: The fan blades on a jet engine make one thousand revolutions in a time of 83.9 ms. What is the…

A: Given data: Angular displacement = 1000 rev Time (t) = 83.9 ms = 83.9×10-3 s Required: The angular…

Q: dl equilibrium position. The distance between the maximum positive and negative position from the…

Q: 14.44 . CALC The balance wheel of a watch vibrates with an angular amplitude 0, angular frequency w,…

Q: y" + 257?y = 100 cos wt Find the period of the oscillator's response (period of the slow sine) for w…

A: Find the period of the oscillator's response (period of the slow sine) for w =15. Round your answer…

Q: A Colpitts oscillator has values of C1 = 0.9 μF, C2 = 30 μF, and L = 104 μH. What is the frequency…

A: In the Colpitts oscillator, the capacitors are in series. So, the equivalent capacitance will be:

Q: Q4. Find the maximum velocity and acceleration of a particle executing SHM of period 10p second and…

A: Given data: Period, T=10 s Amplitude, A=5×10-2m

Q: 3. Two identical disks are connected and oscillate with respect to the pivot as shown figure. The…

Q: A simple harmonic motion is give by y = 5m * cos(36.8). What is the period T in seconds?

Q: (I) If a particle undergoes SHM with amplitude 0.21 m, what is the total distance it travels in one…

A: Amplitude, A =0.21 m

Q: A point rotates about the origin in the xy plane at a constant radius of0.271 m with an angular…

Q: us R = 10.0 cm and mass M = = 30.0 kg and length L. The pendulum swings freely ah axis o…

Q: Q.1 L- Shape slender bar is pivoted at point O as shown in fig. Find the Natural frequency of…

A: Moment of inertia of the above L-shaped slender:- I= I1 + I2 = mL2/3 + mL2/3 = 2mL2/3 COM of rod-1:-…

Q: A certain tuning fork vibrates at a frequency of 160 Hz while each tip of its two prongs has an…

Q: A uniform circular disk whose radius R is 17.0 cm is suspended as a physical pendulum from a point…

A: The radius R=17 cm=0.17 m The period of a physical pendulum T=2πImgdI is the moment of inertiad is…

Q: A simple harmonic motion is give by y = 12m * cos(8t) . What is the maximum acceleration in m/s^2?

A: Given- The equation of simple harmonic motion y = 12m * cos(8t)…

Q: A certain ideal spring elongates 19.7 mm when it is suspended vertically and a block of mass M is…

Q: A small bird’s wings can undergo a maximum displacement amplitude of 4.60 cm (distance from the tip…

A: Given data: Amplitude, A=4.60 cm = 0.046 m Maximum acceleration of the wings, amax=18.7 m/s2

Q: A mass of 0.340kg oscillates up and down on a spring with a spring constant 45.0 N/m. What is the…

A: Given Mass = 0.340 kg Spring constant = 45 N/m To find out Angular Frequency of the motion

Q: A 5.75 kg mass oscillates up and down on a spring that has a force constant of 90 N/m. (a) What is…

A: Given data: Mass (m) = 5.75 kg Force constant of spring (k) = 90 N/m

Q: A particle in simple harmonic motion according to the equation, moves s = TA cos(wt) +TB cos(wt).…

A: given:s=TA cos(ωt)+TB cos(ωt)ω is angular velocityA and B constant

Q: The needle point in a sewing machine moves in Simple Harmonic Motion with frequency of 2.2Hz . At…

A: The given values with suitable variables are listed below. Here, f denotes the frequency, t denotes…

Q: A point rotates about the origin in the ?? plane at a constant radius of 0.266 m with an angular…

Q: Q1. In figures a and b find the angular frequency for the simple harmonics m (b) (a) elll

Q: An SHO has a period of 55.4 s when its amplitude is 55.8 m. If its amplitude is INCREASED by a…

A: GivenTime period, T=55.4 sAmplitude, A=55.8 m

Q: A point rotates about the origin in the ?? plane at a constant radius of 0.211 m with an angular…

A: The amplitude of simple harmonic motion is equal to the radius. Therefore, the amplitude is 0.211m.…

Q: 2. A m: 2.0 kg box IS attached to spring. The motion. of the box is simple harmonic motion, The…

A: Given: The mass of the object is 2 kg. The time period of the oscillation is 1.6 s. The position of…

Q: Q5\2: A damping harmonic oscillator with, m-5 kg, k-180 N/m and c-30 kg/s is subject to a driving…

Q: A piston in a gasoline engine is in simple harmonic motion. The engine is running at the rate of 3…

A: gives that the piston's velocity, From the information given, we write the equation for position as…

Q: A simple pendulum has a length of 52.0 cm and makes 82.0 complete oscillations in 2.00 min. (a) What…

A: (a)

Q: A particle moves in simple harmonic motion with a period of 0.3 s and an amplitude of 6 cm. What are…

Q: An object experiences SHM described by the equation; y (t) = 5.0 sin (20 TT t) where y and t are…

Question

please

Which of the following statements is true about
simple harmonic motion?
The angular frequency increases as the mass
increases.
The amplitude is a function of time.
The spring constant has a unit of kilogram per
second.
The period increases as the mass increases.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

Give an example of a simple harmonic oscillator, specifically noting how its frequency is independent of amplitude.
In an engine, a piston oscillates with simple harmonic motion so that its position varies according to the expression x=5.00cos(2t+6) where x is in centimeters and t is in seconds. At t = 0, find (a) the position of the piston, (b) its velocity, and (c) its acceleration. Find (d) the period and (e) the amplitude of the motion.
A 200-g block is attached to a horizontal spring and executes simple harmonic motion with a period of 0.250 s. The total energy of the system is 2.00 J. Find (a) the force constant of the spring and (b) the amplitude of the motion.
The mechanical energy of an undamped block-spring system is constant as kinetic energy transforms to elastic potential energy and vice versa. For comparison, explain what happens to the energy of a damped oscillator in terms of the mechanical, potential, and kinetic energies.
An automobile with a mass of 1000 kg, including passengers, settles 1.0 cm closer to the road for every additional 100 kg of passengers. It is driven with a constant horizontal component of speed 20 km/h over a washboard road with sinusoidal bumps. The amplitude and wavelength of the sine curve are 5.0 cm and 20 cm, respectively. The distance between the front and back wheels is 2.4 m. Find the amplitude of oscillation of the automobile, assuming it moves vertically as an undamped driven harmonic oscillator. Neglect the mass of the wheels and springs and assume that the wheels are always in contact with the road.
A block with mass m = 0.1 kg oscillates with amplitude .A = 0.1 in at the end of a spring with force constant k = 10 N/m on a frictionless, horizontal surface. Rank the periods of the following situations from greatest to smallest. If any periods are equal, show their equality in your tanking, (a) The system is as described above, (b) The system is as described in situation (a) except the amplitude is 0.2 m. (c) The situation is as described in situation (a) except the mass is 0.2 kg. (d) The situation is as described in situation (a) except the spring has force constant 20 N/m. (e) A small resistive force makes the motion underdamped.
Consider a graphical representation (Fig. 12.3) of simple harmonic motion as described mathematically in Equation 12.6. When the particle is at point on the graph, what can you say about its position and velocity? (a) The position and velocity are both positive. (b) The position and velocity are both negative. (c) The position is positive, and the velocity is zero. (d) The position is negative, and the velocity is zero. (e) The position is positive, and the velocity is negative. (f) The position is negative, and the velocity is positive. Figure 12.3 (Quick Quiz 12.2) An xt graph for a particle undergoing simple harmonic motion. At a particular time, the particles position is indicated by in the graph.
A block of unknown mass is attached to a spring with a spring constant of 6.50 N/m and undergoes simple harmonic motion with an amplitude of 10.0 cm. When the block is halfway between its equilibrium position and the end point, its speed is measured to be 30.0 cm/s. Calculate (a) the mass of the block, (b) the period of the motion, and (c) the maximum acceleration of the block.
For a damped, driven oscillator, show that the average kinetic energy is the same at a frequency of a given number of octaves* above the kinetic energy resonance as at a frequency of the same number of octaves below resonance.