Problem:The blade of a fan is 0.20 m long and makes 20 revolutions/seconds.a) What is the period of the motion of the blade?Given:10 revf =4sSolution:Finda) T-2b) r- 0.3 m, i, - ?c) m= 3g = 0.003 kg , Fe = ?d) ā. -?b) What is its tangential velocity?i, - ?Solutions:2(3.1416)(0.8m)0.4a) What is its period?T-?(5.027m)0.4sT-T-1 0 reT- 0.4 s12.57c) How much force is acting the ball tokeep it in uniform circular motion?Fe =?(0.003kg)(12.57:d) What is the centripetalacceleration of the ball?a. -?ā, -(12.57)-0.8 mm20.8 m(0.003kg)(158.0049158.00490.8 m0.B m(0474 kg 플)- 1975.06%3D0.8 mFe= 0.5925 N

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Description: Problem:The blade of a fan is 0.20 m long and makes 20 revolutions/seconds.a) What is the period of the motion of the blade?Given:10 revf =4sSolution:Finda) T-2b) r- 0.3 m, i, - ?c) m= 3g = 0.003 kg , Fe = ?d) ā. -?b) What is its tangential velocity

A) Given Frequency f = 20 rev /sec Time period T = 1/f So T = 1/20 T = 0.05 sec

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The blade of a fan is 0.20 m long and makes 20 revolutions/seconds a) What is the period of the motion of the blade?

Classical Dynamics of Particles and Systems

5th Edition

ISBN:9780534408961

Author:Stephen T. Thornton, Jerry B. Marion

Publisher:Stephen T. Thornton, Jerry B. Marion

Chapter10: Motion In A Noninertial Reference Frame

Section: Chapter Questions

Problem 10.5P

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