Multiple choice in data structures void doo(node*root){ if(root !=0) { node*p=root; while(root->next!=0) root=root->next; p->data=root->data; } What is this code do?
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Multiple choice in data structures
void doo(node<int>*root){
if(root !=0) { node<int>*p=root;
while(root->next!=0) root=root->next;
p->data=root->data;
}
What is this code do?
swap the first item with the last item in the linked list
set the first item in the linked list as the last item
doesn't do anything because the root parameter is passed by value
change the root item in the binary tree with the farthest leaf item
Step by step
Solved in 2 steps
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- class Node: def __init__(self, e, n): self.element = e self.next = n class LinkedList: def __init__(self, a): # Design the constructor based on data type of a. If 'a' is built in python list then # Creates a linked list using the values from the given array. head will refer # to the Node that contains the element from a[0] # Else Sets the value of head. head will refer # to the given LinkedList # Hint: Use the type() function to determine the data type of a self.head = None # To Do # Count the number of nodes in the list def countNode(self): # To Do # Print elements in the list def printList(self): # To Do # returns the reference of the Node at the given index. For invalid index return None. def nodeAt(self, idx): # To DoC++ ProgrammingActivity: Linked List Stack and BracketsExplain the flow of the code not necessarily every line, as long as you explain what the important parts of the code do. The code is already correct, just explain the flow #include "stack.h" #include "linkedlist.h" // SLLStack means Singly Linked List (SLL) Stack class SLLStack : public Stack { LinkedList* list; public: SLLStack() { list = new LinkedList(); } void push(char e) { list->add(e); return; } char pop() { char elem; elem = list->removeTail(); return elem; } char top() { char elem; elem = list->get(size()); return elem; } int size() { return list->size(); } bool isEmpty() { return list->isEmpty(); } };1.Assume some Node class with info link fields . Complete this method in class List that returns a reference to the node containing the data item in the argument findThis, Assume that findThis is in the list public class list { protected Node head ; Protected int size ; Public Node find (char find this) { Node curr = head; while(curr != null) { if(curr.info == findThis) return curr; curr = curr.link; } return -1; } }
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