Data Structures and algorithms: Topic: Doubly and circular Linked Lists in java: Please solve this on urgent basis: Attach output's picture and explain every statement in commments:   Create a doubly Linked list,  So far you have come across with numbers that are prime and you have a great knowledge about them using that knowledge help Alice solve the problem of finding all the numbers that are prime and collectively return the sum of those prime numbers stored in doubly linked list. You can use more than 1 function to solve this problem. For example               Linked List contains Data: 8,12,3,17,11,             Output: 31             Explanation:   3+17+11 = 31

Java language NOTE THAT WE ARE USING **LINKED LISTS** SEE PICTURES FOR ALL INFORMATION Solve method public boolean inSort(double elt) { //code goes here } please and thank you!!!!

File TesSLL.java contains a driver that allows you to experiment with these methods. Compile and run TestSLL, and play around with it to see how it works. Then add the following methods to the SinglyLinkedList class. For each, add an option to the driver to test it. Do this in incremental steps!! This means, implement and test the methods one at a time.

JAVA :

A consecutive sequence a list of numbers that are organized in increasing order with the next eleme. one bigger than the current. Write a non-recursive method "lengthConsec", which takes an IntNode myList as the parameter and returns the length of the consecutive sequence in myList. To simplify the implementation, you can assume that there is no more than one consecutive sequence in the list. For example, in the following linked list, the consecutive sequence begins at node "5" and ends at node "7", so lengthConsec (myList) should return 3 in this case. myList 8 13 4 public class IntNode { 12 private int m_data; private IntNode m_link; Consecutive sequence 6 7 28

Java Given main() in the ShoppingList class, define an insertAtEnd() method in the ItemNode class that adds an element to the end of a linked list. DO NOT print the dummy head node. Ex. if the input is: 4 Kale Lettuce Carrots Peanuts  where 4 is the number of items to be inserted; Kale, Lettuce, Carrots, Peanuts are the names of the items to be added at the end of the list. The output is: Kale Lettuce Carrots Peanuts  Second image is ItemNode

Java language Write a method to insert an array of elements at index in a single linked list and then display this list. The method receives this array by parameters

Lab 14.1 Beginning to build an Arrazlizt recursively In this sequence of problems we practice recursion by abandoning our reliance on iteration. We resolve to solve a sequence of problems without using while or for loops. Instead we will think recursively and look at the world through a different lens. Recursion is all about solving a large problem by using the solution to a similar smaller problem. The brilliant thing about recursion is that you can assume you already know how to solve the smaller problem. The goal is to demonstrate how the smaller solution relates to the larger problem at hand. For example, suppose you want to print all binary strings of length 3 and you already know how to print all binary strings of length 2. Here they are: 00 01 10 11 How can we solve the larger problem with a list of strings of length 2? Add a "0" or "1", right? So here is the solution to the larger problem: 00 + 0 = 000 01 + 0 = 010 10 + 0 = 100 11 +0 = 110 and 00 + 1 = 001 01 + 1 = 011 10 + 1 =…

Write the following method that returns the sum of all numbersin an ArrayList:public static double sum(ArrayList<Double> list)Write a test program that prompts the user to enter five numbers, stores them inan array list, and displays their sum.

In Java please help with the following:   Sees whether this list is empty.@return True if the list is empty, or false if not. */ public boolean isEmpty(); } // end ListInterface Hint:Node class definition should look something like: public class Node<T> { T element; Node next; Node prev; public Node(T element, Node next, Node prev) { this.element = element;this.next = next;this.prev = prev; } }