Mutation in the operator that reduces the affinity of the operator for the repressor protein (operator-constitutive mutants = 0°)? Mutation in the promoter that reduces the affinity of the promoter for RN. polymerase (P)? Mutation in the repressor gene such that the protein has lost the ability to bind allolactose (superrepressor mutant = I³)? Mutation in the repressor gene such that the protein has lost the ability to bind the operator (I)? Gene Status normal Oc P IS I + lactose - lactose

Mutation in the operator that reduces the affinity of the operator for the repressor protein (operator-constitutive mutants = 0°)? Mutation in the promoter that reduces the affinity of the promoter for RN. polymerase (P)? Mutation in the repressor gene such that the protein has lost the ability to bind allolactose (superrepressor mutant = I³)? Mutation in the repressor gene such that the protein has lost the ability to bind the operator (I)? Gene Status normal Oc P IS I + lactose - lactose

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter9: Gene Expression And Gene Regulation

Section: Chapter Questions

Problem 10QP: The pre-mRNA transcript and protein made by several mutant genes were examined. The results are...

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Consider the Rho-dependent terminator sequence 5’CCCAGCCCGCCUAAUGAGCGGCCUUUUUUUU-3’. What affect would a point mutation at any one of the bolded and underlined nucleotides disrupt termination of transcription? Group of answer choices Mutation in one of these nucleotides would disrupt base pairing, preventing the formation of the hairpin and disrupting termination. Mutation in one of these nucleotides would have no affect on base pairing, so the termination hairpin is formed and termination proceeds. Mutation in one of these nucleotides would not disrupt base pairing, but would prevent the formation of the hairpin and disrupt termination. Mutation in one of these nucleotides would disrupt base pairing, but not affect the formation of the hairpin and termination proceeds.
Please answer both questions Explain five ways that eukaryotic gene regulation is more complex than bacterial gene regulation? Mutations in the promoter region of the B-globin gene indicate that some areas are more sensitive than others. When mutations occur in consensus sequences(modular elements such as GC box, CAAT box, and TATA box), does transcription usually increase or decrease? Explain.
A bacterial species has a hypothetical sigma promoter that has the following sequence: TTGGCA - 18 bases - TATAAT What change in the level of transcription would there be if the sequence was mutated to: TTCGCA -18 bases -TATAAT Group of answer choices 1.The mutation would inhibit the promoter thereby inhibiting transcription 2.No change the consensus TATAAT sequence in the same. 3.The mutation would move the promoter away from consensus and reduce the level of transcription 4.The mutation would bind the promoter to the consensus and produce normal levels of transcription
Consider Figure 3, which shows some features of a eukaryotic gene. A, B, C are exons while 1, 2 are introns. E marks an enhancer. The 5’ UTR and 3’ UTR are also marked. Which one of the following features would you expect to NOT be included in the primary RNA (before any processing has occurred) that results from transcription of this gene? Region marked E Region marked 5’ UTR Regions marked A, B and C Regions marked 1 and 2
Wild-type E. coli grow best at 37oC, but can grow efficiently at temperatures up to 42oC. An E. coli strain has a mutation in the gene encoding rho protein that results in a stable protein at 37oC, but this mutant protein ceases to function at 42oC. When bacteria bearing this temperature-sensitive mutation are raised at 42oC, which of the following effects would you expect to see? Explain your reasoning for each of the 5 optionsa. Transcription does not take placeb. All RNA molecules are shorter than normalc. All RNA molecules are longer than normald. Some RNA molecules are longer than normal e. RNA is transcribed from both strands
How do you think that transcription randomizes positions of nucleosomes and repression restores the ordering after transcription? How might you test to see if there was an exchange of histone subunits during transcription or if the nucleosome is truly transferred as a single unit? Would you expect the DNA band representing the distance from the restriction enzyme site to the hypersensitive site to be a single band or a smear? Defend your answer.
A mutation in the trp repressor gene that prevents the apo-repressor from binding the co-repressor What is the correct option from the choices below? causes the Trp repressor to permanently bind the trp operator. leads to a high level of transcription initiation from the trp promoter, even when tryptophan is present in the medium. does not lead to a high concentration of mRNA molecules that code for the structural genes trp E, D, C, B, A, when tryptophan is present in the medium, because attenuation of the operon will still work. a and b, but not c b and c, but not a
Rsearcher has discovered that one human promoter is responsible for producing two different proteins (Protein K and Protein B) from the same gene. In Kidney cells it is responsible for the production of Protein K, while in Brain cells it is responsible for the production of Protein B. How are these different proteins being produced from the same gene? Describe the mechanism
Consider the Rho-dependent terminator sequence 5’CCCAGCCCGCCUAAUGAGCGGCCUUUUUUUU-3’. What affect would a point mutation at any one of the bolded and underlined nucleotides disrupt termination of transcription? Group of answer choices 1.Mutation in one of these nucleotides would disrupt base pairing, but not affect the formation of the hairpin and termination proceeds. 2.Mutation in one of these nucleotides would have no affect on base pairing, so the termination hairpin is formed and termination proceeds. 3.Mutation in one of these nucleotides would not disrupt base pairing, but would prevent the formation of the hairpin and disrupt termination. 4.Mutation in one of these nucleotides would disrupt base pairing, preventing the formation of the hairpin and disrupting termination.
When an EcoR1 fragment, which represents the coding region of a human gene X, is cloned into the EcoR1 site upstream of the coding region of a prokaryotic gene (such as GST) (i.e., to make a X-GST fusion protein), what is the chance of an in-frame fusion? Please draw a diagram to explain your answer. Do you need to delete the stop codon of the X gene coding region before fusing it to the GST coding region? Please draw a diagram to explain your answer. Notes: It is NOT known which strand of the human gene X is the template strand for transcription. 2) Both X and GST protein fragments must be produced correctly)
Which of the following is least related to the other items? Group of answer choices inducer repressor operator enhancers 2. A scientist observing a cell during gene expression would be able to easily distinguish it as a prokaryotic cell by which of the following observations? Group of answer choices as soon as the DNA introns are removed from the template after the 5' caps are converted to mRNA after a transcription initiation complex has been formed during transcription once the pre-mRNA has been converted to mRNA
A bacterial species has a hypothetical sigma promoter that has the following sequence: TTGGCA - 18 bases - TATAAT What change in the level of transcription would there be if the sequence was mutated to: TTCGCA -18 bases -TATAAT 1.The mutation would move the promoter away from consensus and reduce the level of transcription 2.No change the consensus TATAAT sequence in the same. 3.The mutation would bind the promoter to the consensus and produce normal levels of transcription 4.The mutation would inhibit the promoter thereby inhibiting transcription