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n an enzyme reaction the enzyme has a KM of 72 mM. At which substrate concentration will the rate of the reaction be 91% of Vmax? Substrate concentration that leads to 91 % of Vmax = mM What does the parameter Vmax tell you about an enzyme?

n an enzyme reaction the enzyme has a KM of 72 mM. At which substrate concentration will the rate of the reaction be 91% of Vmax? Substrate concentration that leads to 91 % of Vmax = mM What does the parameter Vmax tell you about an enzyme?

Biochemistry
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
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In an enzyme reaction the enzyme has a KM of 72 mM. At which substrate concentration will the rate of the reaction be 91% of Vmax? Substrate concentration that leads to 91 % of Vmax= mM What does the parameter Vmax tell you about an enzyme? a) How the affinity of the enzyme is for its substrate b) How much enzyme is required to achieve half maximum rate of the reaction c) How much of the enzyme is required to completely turn the substrate into the product of a reaction d) How the enzyme behaves at very low substrate concentrations e) How the enzyme behaves at very high substrate concentrations What would happen if you increased the concentration of the enzyme twofold? a) Vmax would also increase twofold, but KM would stay constant b) Vmax and KM would both increase twofold c) Vmax would stay constant, but KM would increase twofold d) Vmax and KM would both stay constant e) Vmax would be halved, but KM stays constant
Transcribed Image Text:In an enzyme reaction the enzyme has a KM of 72 mM. At which substrate concentration will the rate of the reaction be 91% of Vmax? Substrate concentration that leads to 91 % of Vmax= mM What does the parameter Vmax tell you about an enzyme? a) How the affinity of the enzyme is for its substrate b) How much enzyme is required to achieve half maximum rate of the reaction c) How much of the enzyme is required to completely turn the substrate into the product of a reaction d) How the enzyme behaves at very low substrate concentrations e) How the enzyme behaves at very high substrate concentrations What would happen if you increased the concentration of the enzyme twofold? a) Vmax would also increase twofold, but KM would stay constant b) Vmax and KM would both increase twofold c) Vmax would stay constant, but KM would increase twofold d) Vmax and KM would both stay constant e) Vmax would be halved, but KM stays constant
You measure a Vmax of 123 µM/min when using an enzyme concentration of 11.3 µg/mL in the test tube. You know that the enzyme has a relative molecular mass of 23 kDa. From this information, calculate the turnover number of the enzyme. The turnover number is minute-¹
Transcribed Image Text:You measure a Vmax of 123 µM/min when using an enzyme concentration of 11.3 µg/mL in the test tube. You know that the enzyme has a relative molecular mass of 23 kDa. From this information, calculate the turnover number of the enzyme. The turnover number is minute-¹
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