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Name : Murta Qasm Grop a) Given data: P = 100 kPa a = 20% T = -26 C Need to determine the mass refrigerant and the rate of h kitchen air. b)

Name : Murta Qasm Grop a) Given data: P = 100 kPa a = 20% T = -26 C Need to determine the mass refrigerant and the rate of h kitchen air. b)

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)
Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)
8th Edition
ISBN:9781305387102
Author:Kreith, Frank; Manglik, Raj M.
Publisher:Kreith, Frank; Manglik, Raj M.
Chapter6: Forced Convection Over Exterior Surfaces
Section: Chapter Questions
Problem 6.12P
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Hello sir, I know a strange request, please I want the same solution, but handwritten in the paper in a beautiful and clear font, please, I attached a picture of the same paper or another, natural, and most importantly a paper. A beautiful line
Name : Murtaza Ali Qasm Grop: B1 a) Given data: P = 100 kPa x = 20% Т, — — 26°С Need to determine the mass flow rate of the refrigerant and the rate of heat rejected to the kitchen air. b) Use the R-134a table, At Pi = 100 kPa and x = 20%, h = 60. 708 kJ/kg Similarly at T2 = -26°C h2 = 234. 75 kJ/kg Apply the energy balance concept, mh1 + Qµ = mh, h2-hi W×COPR [coPR = ) m = h2-hị 0,6x1,2 234.75-60.709 m = 0. 00414 kg/s Apply the energy balance concept on refrigerator, W = QH - QL = W + QL W(1+ COPR) = 0. 6(1 + 1. 2) QH = 1. 32 kW = 1320 W
Transcribed Image Text:Name : Murtaza Ali Qasm Grop: B1 a) Given data: P = 100 kPa x = 20% Т, — — 26°С Need to determine the mass flow rate of the refrigerant and the rate of heat rejected to the kitchen air. b) Use the R-134a table, At Pi = 100 kPa and x = 20%, h = 60. 708 kJ/kg Similarly at T2 = -26°C h2 = 234. 75 kJ/kg Apply the energy balance concept, mh1 + Qµ = mh, h2-hi W×COPR [coPR = ) m = h2-hị 0,6x1,2 234.75-60.709 m = 0. 00414 kg/s Apply the energy balance concept on refrigerator, W = QH - QL = W + QL W(1+ COPR) = 0. 6(1 + 1. 2) QH = 1. 32 kW = 1320 W
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