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nd the regression equation, letting the diameter be the predictor (x) variable. Find the best predicted circumference of a marble with a diameter of 1.5 cm. How does the result compare to the actual circumference of 4.7 cm? Use a significance Baseball Basketball Golf Soccer Tennis Ping-Pong Volleyball ameter 7.4 24.3 4.2 21.9 7.1 ircumference 23.2 76.3 13.2 68.8 22.3 4.1 21.2 12.9 66.6 Click the icon to view the critical values of the Pearson correlation coefficient r he regression equation is y=+K Cound to five decimal places as needed.) he best predicted circumference for a diameter of 1.5 cm is c cm. Cound to one decimal place as needed.) ow does the result compare to the actual circumference of 4.7 cm? A. Since 1.5 cm is beyond the scope of the sample diameters, the predicted value yields a very different circumference. B. Even though 1.5 cm is beyond the scope of the sample diameters, the predicted value yields the actual circumference. OC. Even though 1.5 cm is within the scope of the sample diameters, the predicted value yields a very different circumference. D. Since 1.5 cm is within the scope of the sample diameters, the predicted value yields the actual circumference.

nd the regression equation, letting the diameter be the predictor (x) variable. Find the best predicted circumference of a marble with a diameter of 1.5 cm. How does the result compare to the actual circumference of 4.7 cm? Use a significance Baseball Basketball Golf Soccer Tennis Ping-Pong Volleyball ameter 7.4 24.3 4.2 21.9 7.1 ircumference 23.2 76.3 13.2 68.8 22.3 4.1 21.2 12.9 66.6 Click the icon to view the critical values of the Pearson correlation coefficient r he regression equation is y=+K Cound to five decimal places as needed.) he best predicted circumference for a diameter of 1.5 cm is c cm. Cound to one decimal place as needed.) ow does the result compare to the actual circumference of 4.7 cm? A. Since 1.5 cm is beyond the scope of the sample diameters, the predicted value yields a very different circumference. B. Even though 1.5 cm is beyond the scope of the sample diameters, the predicted value yields the actual circumference. OC. Even though 1.5 cm is within the scope of the sample diameters, the predicted value yields a very different circumference. D. Since 1.5 cm is within the scope of the sample diameters, the predicted value yields the actual circumference.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter4: Equations Of Linear Functions
Section4.6: Regression And Median-fit Lines
Problem 6PPS
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Find the regression equation, letting the diameter be the predictor (x) variable. Find the best predicted circumference of a marble with a diameter of 1.5 cm. How does the result compare to the actual circumference of 4.7 cm? Use a significance level of 0.05. Baseball Basketball Golf Soccer Tennis Ping-Pong Volleyball Diameter 74 24.3 4.2 21.9 7.1 4.1 21.2 Circumference 23.2 76.3 13.2 68.8 22.3 12.9 66.6 Click the icon to view the critical values of the Pearson correlation coefficient r. The regression equation is y + x (Round to five decimal places as needed.) The best predicted circumference for a diameter of 1.5 cm is cm. (Round to one decimal place as needed.) How does the result compare to the actual circumference of 4.7 cm? O A. Since 1.5 cm is beyond the scope of the sample diameters, the predicted value yields a very different circumference. OB. Even though 1.5 cm is beyond the scope of the sample diameters, the predicted value yields the actual circumference. OC. Even though 1.5 cm is within the scope of the sample diameters, the predicted value yields a very different circumference. O D. Since 1.5 cm is within the scope of the sample diameters, the predicted value yields the actual circumference.
Transcribed Image Text:Find the regression equation, letting the diameter be the predictor (x) variable. Find the best predicted circumference of a marble with a diameter of 1.5 cm. How does the result compare to the actual circumference of 4.7 cm? Use a significance level of 0.05. Baseball Basketball Golf Soccer Tennis Ping-Pong Volleyball Diameter 74 24.3 4.2 21.9 7.1 4.1 21.2 Circumference 23.2 76.3 13.2 68.8 22.3 12.9 66.6 Click the icon to view the critical values of the Pearson correlation coefficient r. The regression equation is y + x (Round to five decimal places as needed.) The best predicted circumference for a diameter of 1.5 cm is cm. (Round to one decimal place as needed.) How does the result compare to the actual circumference of 4.7 cm? O A. Since 1.5 cm is beyond the scope of the sample diameters, the predicted value yields a very different circumference. OB. Even though 1.5 cm is beyond the scope of the sample diameters, the predicted value yields the actual circumference. OC. Even though 1.5 cm is within the scope of the sample diameters, the predicted value yields a very different circumference. O D. Since 1.5 cm is within the scope of the sample diameters, the predicted value yields the actual circumference.
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