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Social ScienceNolumeb.50 mLintialFinalmassig1.223gL29591.214 90. 0omLlo 50mlIZ.48mL5.१४m८212.48mय19.1DMLla. l02mL19.10ml25DmL5.9 mL1.2049
How do I calculate the number of moles of potassium permanganate used in each titration?
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Nolume b.50 mL intial Final massig 1.223g L2959 1.214 9 0. 0omL lo 50ml IZ.48mL 5.१४m८ 2 12.48mय 19.1DML la. l02mL 19.10ml 25DmL 5.9 mL 1.2049
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Since you have posted a question with multiple sub-parts, we will solve first three subparts for you. To get remaining sub-part solved please repost the complete question and mention the sub-parts to be solved.
Given information:
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Mass (g) Initial volume Final volume Volume used (mL) 0.00 mL (mL) 6.50 mL (mL) 6.50 mL 1.223 g 1.295 g 1.214 g 1 6.50 mL 12.48 mL 2 3 12.48 mL 5.98 mL 19.10 mL 6.62 mL
Mole is the amount of the substance that contains the same number of particles or atoms or molecule...
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Given mass n= Molar mass
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