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- In a river with a constant flow rate, the factory releases wastewater containing NaCl at a concentration of 200 mmol / L to the river at 20.0 L / s. The Na+ and Cl- concentrations at the downstream observation point were 1.00 mmol / L and 0.800 mmol / L, respectively. What is the river flow Q and Cl- concentration before the inflow of drainage? The river originally contains 0.500 mmol / L of Na+.Beaker 0.00200 M Fe(NO3)3, mL 0.00200 M NaSCN, mL total volume, mL 1 3.000 2.000 10.00 2 3.000 3.000 10.00 3 3.000 4.000 10.00 4 3.000 5.000 10.00 5 (blank) 3.000 0.000 10.00 In Solutions 1-4 you are adding successively larger volumes of 0.00200M SCN- to the Fe3+ solution and diluting to 10.00 ml. Calculate the final diluted molarity of SCN- in solution #1 Your answer should have 3 sig figs =150 kmol of an aqueous phosphoric acid solution contains S mol percent H3P04. The solution is concentrated by adding pure phosphoric acid at a rate of 20L per minute. Write a differential mole balance on phosphoric acid and provide an initial condition. Solve the balance to abtain an expression vdor np(t) . Use the result to derive an expression far xp(t), the mole fraction of phosphoric acid in the solution. How long will it take to concentrate the solution to IS percent H3P04 ?
- Use the following atomic masses (in g/mol): K = 39.1; Mn = 54.94; O = 16; H = 1; P = 30.97; C = 12.01; Na = 23; Mg = 24.31; S = 32.06; Zn = 65.38; Cu = 63.55 In the standardization of Hydrochloric Acid against pure anhydrous Sodium Carbonate, 1mL was found to be equivalent to 0.05g of the primary standard. Compute for the normality of the acid.There's 1 drink (and you are asked to determine the glucose concentration in the drink in the units of g/100mL. (Why these units? Well, once you have the concentrations in g/100mL you will be able to compare your values with the nutritional values given on the drink bottles’ labels). The sample of the drink was diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for you is that the dilution factor will need to be taken into consideration in your calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). You measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar). Glucose Concentration in mM of drink =…There's 1 drink (and you are asked to determine the glucose concentration in the drink in the units of g/100mL. (Why these units? Well, once you have the concentrations in g/100mL you will be able to compare your values with the nutritional values given on the drink bottles’ labels). The sample of the drink was diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for you is that the dilution factor will need to be taken into consideration in your calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). You measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar). Glucose Concentration in mM of drink =…
- Electrolytic manganese dioxide can be prepared from manganese carbonate ore by crushing,milling and leaching the ore in sulphuric acid. Manganese sulphate is crystallised from thesolution, redissolved and electrolysed to give the manganese dioxide.If the crystallisation were performed in a 30m3 tank and the concentration of the solutionentering the tank were 160 grams per litre and left the tank at 40 grams per litre, how muchMnSO4.5H2O would be produced.Stock iron(II) solution (200Ug mL-1 Fe) ferrous ammonium sulfate hexahydrate mass= 0.1437g, transfer it to a 100 ml beaker. add 15 ml approx of water and 15m1 'approx of dilute sulphuric acid (2M H2SO.). then transfer FeII to 100 ml flask makeup to the mark with water. calculate the moles of ferrous ammonium sulfate hexahydrate solution in unit ug/mL.