Now if z is the initial mass of magnesium and y is the initial mass of aluminum, the total number of moles of hydrogen gas produced, n, can be expressed as n= 0.0411z +0.0556y. If the total mass of the two metals is 0.250 g, then z+y=0.250, and therefore I= 0.250 – y. Substitute for I in the first equation to express n in terms of y n=0.0411(0.250 – y) +0.0556y The value of n can be found using the ideal gas law. Part C Taking into account the vapour pressure of water, how many moles of hydrogen gas, n, are present in 303 mL at 752 Torr and 29 °C? The value of the gas constant Ris 0.08314 L bar mol-1 K-1 You may also find the conversion factors1 bar = 750 Torr and Tx = Tc + 273 useful. Express the number of moles to three significant figures. • View Available Hint(s) n= 1,16x10-2 mol Submit Previous Answers v Correct Part D What is the mass percentage of aluminum in this alloy? Express your answer numerically. > View Available Hint(s) Iνα ΑΣφ %

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Chapter3: Calculations With Chemical Formulas And Equaitons
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Constane
Fenodic
Now if a is the initial mass of magnesium and y is the initial mass of aluminum, the total number of moles of hydrogen gas produced, n, can be expressed as
n= 0.0411a +0.0556y.
If the total mass of the two metals is 0.250 g. then x+y = 0.250, and therefore x = 0.250 – y.
Substitute for in the first equation to express n in terms of y
n= 0.0411(0.250 – y) + 0.0556y
The value of n can be found using the ideal gas law.
Part C
Taking into account the vapour pressure of water, how many moles of hydrogen gas, n, are present in 303 mL at 752 Torr and 29 °C?
The value of the gas constant Ris 0.08314 L bar mol-1 K-1 You may also find the conversion factors1 bar = 750 Torr and Tk = T + 273 useful.
Express the number of moles to three significant figures.
• View Available Hint(s)
n = 1.16×10-2 mol
Submit
Previous Answers
v Correct
Part D
What is the mass percentage of aluminum in this alloy?
Express your answer numerically.
• View Available Hint(s)
nν ΑΣφ
%
Transcribed Image Text:Constane Fenodic Now if a is the initial mass of magnesium and y is the initial mass of aluminum, the total number of moles of hydrogen gas produced, n, can be expressed as n= 0.0411a +0.0556y. If the total mass of the two metals is 0.250 g. then x+y = 0.250, and therefore x = 0.250 – y. Substitute for in the first equation to express n in terms of y n= 0.0411(0.250 – y) + 0.0556y The value of n can be found using the ideal gas law. Part C Taking into account the vapour pressure of water, how many moles of hydrogen gas, n, are present in 303 mL at 752 Torr and 29 °C? The value of the gas constant Ris 0.08314 L bar mol-1 K-1 You may also find the conversion factors1 bar = 750 Torr and Tk = T + 273 useful. Express the number of moles to three significant figures. • View Available Hint(s) n = 1.16×10-2 mol Submit Previous Answers v Correct Part D What is the mass percentage of aluminum in this alloy? Express your answer numerically. • View Available Hint(s) nν ΑΣφ %
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