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Nuclear Binding Energy II Calculate the binding energy per nucleon for the nucleus. (Atomic masses: iron-56 = 55.9349 amu; hydrogen-1 = 1.0078 amu; mass of neutron = 1.0087 amu) We must first calculate the mass defect (Am) for 56Fe. Since atomic masses (which include the electrons) are given, we must decide how to account for the electron mass: 55.9349 = mass of Fe atom = mass of nucleus + 26 me 1.0078 = mass of H atom = mass of nucleus + me Thus, since a 56Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 - 26 me) - [26(1.0078 - me) + 30(1.0087)]. Solve for Am. Am = -0.5289 amu Submit What is the energy change? AE = -7.9x10^-11 J/nucleus Submit What is the binding energy (BE) per nucleon? BE per nucleon = X MeV/nucleon

Nuclear Binding Energy II Calculate the binding energy per nucleon for the nucleus. (Atomic masses: iron-56 = 55.9349 amu; hydrogen-1 = 1.0078 amu; mass of neutron = 1.0087 amu) We must first calculate the mass defect (Am) for 56Fe. Since atomic masses (which include the electrons) are given, we must decide how to account for the electron mass: 55.9349 = mass of Fe atom = mass of nucleus + 26 me 1.0078 = mass of H atom = mass of nucleus + me Thus, since a 56Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 - 26 me) - [26(1.0078 - me) + 30(1.0087)]. Solve for Am. Am = -0.5289 amu Submit What is the energy change? AE = -7.9x10^-11 J/nucleus Submit What is the binding energy (BE) per nucleon? BE per nucleon = X MeV/nucleon

Principles of Modern Chemistry
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter19: Nuclear Chemistry
Section: Chapter Questions
Problem 36P
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INTERACTIVE EXAMPLE Nuclear Binding Energy II Calculate the binding energy per nucleon for the nucleus. (Atomic masses: iron-56 = 55.9349 amu; hydrogen-1 = 1.0078 amu; mass of neutron = 1.0087 amu) We must first calculate the mass defect (Am) for 56F.. Since atomic masses (which include the electrons) are given, we must decide how to account for the electron mass: 55.9349 = mass of Fe atom = mass of nucleus + 26 me 1.0078 = mass of H atom mass of nucleus + me Thus, since a 56Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 26 m.) - [26(1.0078 - me) + 30(1.0087)]. Solve for Am. Am = -0.5289 amu Submit What is the energy change? AE = -7.9x10A-11 J/nucleus Submit What is the binding energy (BE) per nucleon? BE per nucleon = X MeV/nucleon
Transcribed Image Text:INTERACTIVE EXAMPLE Nuclear Binding Energy II Calculate the binding energy per nucleon for the nucleus. (Atomic masses: iron-56 = 55.9349 amu; hydrogen-1 = 1.0078 amu; mass of neutron = 1.0087 amu) We must first calculate the mass defect (Am) for 56F.. Since atomic masses (which include the electrons) are given, we must decide how to account for the electron mass: 55.9349 = mass of Fe atom = mass of nucleus + 26 me 1.0078 = mass of H atom mass of nucleus + me Thus, since a 56Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 26 m.) - [26(1.0078 - me) + 30(1.0087)]. Solve for Am. Am = -0.5289 amu Submit What is the energy change? AE = -7.9x10A-11 J/nucleus Submit What is the binding energy (BE) per nucleon? BE per nucleon = X MeV/nucleon
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