nutritionist claims that the mean tuna consumption by a person is 3.6 pounds per year. A sample of 80 people shows that the mean tuna consumption by a person is 3.4 pounds per year. Assume the population standard deviation is 1.03 ounds. At a 0.06, can you reject the claim? ) Identify the null hypothesis and alternative hypothesis. DA. Ho: us3.6 O B. Ho: H> 3.6 HH53.6 OC. Ho: H>3.4 H: us34 Hi>3.6 O D. Ho: H3.4 OE. Ho: Hs34 Hu>3.4 OF. Ho: H=3.6 Hu3.6 H=3.4 ) Identify the standardized test statistic, z. (Round to two decimal places as needed.) ) Find the P-value. Hint: Keep in mind that P-value depends on the type of test. Left-tailed test Pvalue-Area Right-tailed test: P-value=1-Area Two-tailed test: P-value=2'Area (where Area = the number from the table) value = (Round to three decimal places as needed.) ) Decide whether to reject or fail to reject the null hypothesis. Compare P with a and then State your conclusion. DA. Fail to reject Ho. There is sufficient evidence to reject the claim that mean tuna consumption equal to 3.6 O B. Reject Ho. There is sufficient evidence to reject the claim that mean tuna consumption is equal to 3.6 pounds. pounds. DC. Fail to reject Ho. There is not sufficient evidence to reject the claim that mean tuna consumption is equal to 3.6 O D. Reject Ho. There is not sufficient evidence reject the claim that mean tuna consumption is equal to 3.6 pounds. pounds.

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
icon
Related questions
Question
A nutritionist claims that the mean tuna consumption by a person is 3.6 pounds per year. A sample of 80 people shows that the mean tuna consumption by a person is 3.4 pounds per year. Assume the population standard deviation is 1.03
pounds. At a= 0.06, can you reject the claim?
(a) Identify the null hypothesis and alternative hypothesis.
O A. Ho: Hs3.6
HiH>3.6
O B. Ho: H>3.6
H: us3.6
OC. Ho: H>3.4
H:us3.4
OD. Ho: H#3.4
HiH=3.4
O E. Ho: H53.4
H:u>3.4
OF. Ho: H=3.6
Hi p#3.6
(b) Identify the standardized test statistic, z.
z= (Round to two decimal places as needed.)
(c) Find the P-value.
Hint: Keep in mind that P-value depends on the type of test.
Left-tailed test: P-value=Area
Right-tailed test: P-value=1-Area
Two-tailed test: P-value=2'Area
(where Area = the number from the table)
P-value = (Round to three decimal places as needed.)
(d) Decide whether to reject or fail to reject the null hypothesis.
Compare P with a and then State your conclusion.
O A. Fail to reject Ho. There is sufficient evidence to reject the claim that mean tuna consumption is equal to 3.6
O B. Reject Ho. There is sufficient evidence to reject the claim that mean tuna consumption is equal to 3.6 pounds.
pounds.
O C. Fail to reject Ho. There is not sufficient evidence to reject the claim that mean tuna consumption is equal to 3.6
O D. Reject Ho. There is not sufficient evidence to reject the claim that mean tuna consumption is equal to 3.6 pounds.
pounds.
Transcribed Image Text:A nutritionist claims that the mean tuna consumption by a person is 3.6 pounds per year. A sample of 80 people shows that the mean tuna consumption by a person is 3.4 pounds per year. Assume the population standard deviation is 1.03 pounds. At a= 0.06, can you reject the claim? (a) Identify the null hypothesis and alternative hypothesis. O A. Ho: Hs3.6 HiH>3.6 O B. Ho: H>3.6 H: us3.6 OC. Ho: H>3.4 H:us3.4 OD. Ho: H#3.4 HiH=3.4 O E. Ho: H53.4 H:u>3.4 OF. Ho: H=3.6 Hi p#3.6 (b) Identify the standardized test statistic, z. z= (Round to two decimal places as needed.) (c) Find the P-value. Hint: Keep in mind that P-value depends on the type of test. Left-tailed test: P-value=Area Right-tailed test: P-value=1-Area Two-tailed test: P-value=2'Area (where Area = the number from the table) P-value = (Round to three decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis. Compare P with a and then State your conclusion. O A. Fail to reject Ho. There is sufficient evidence to reject the claim that mean tuna consumption is equal to 3.6 O B. Reject Ho. There is sufficient evidence to reject the claim that mean tuna consumption is equal to 3.6 pounds. pounds. O C. Fail to reject Ho. There is not sufficient evidence to reject the claim that mean tuna consumption is equal to 3.6 O D. Reject Ho. There is not sufficient evidence to reject the claim that mean tuna consumption is equal to 3.6 pounds. pounds.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Recommended textbooks for you
MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
Statistics
ISBN:
9781119256830
Author:
Amos Gilat
Publisher:
John Wiley & Sons Inc
Probability and Statistics for Engineering and th…
Probability and Statistics for Engineering and th…
Statistics
ISBN:
9781305251809
Author:
Jay L. Devore
Publisher:
Cengage Learning
Statistics for The Behavioral Sciences (MindTap C…
Statistics for The Behavioral Sciences (MindTap C…
Statistics
ISBN:
9781305504912
Author:
Frederick J Gravetter, Larry B. Wallnau
Publisher:
Cengage Learning
Elementary Statistics: Picturing the World (7th E…
Elementary Statistics: Picturing the World (7th E…
Statistics
ISBN:
9780134683416
Author:
Ron Larson, Betsy Farber
Publisher:
PEARSON
The Basic Practice of Statistics
The Basic Practice of Statistics
Statistics
ISBN:
9781319042578
Author:
David S. Moore, William I. Notz, Michael A. Fligner
Publisher:
W. H. Freeman
Introduction to the Practice of Statistics
Introduction to the Practice of Statistics
Statistics
ISBN:
9781319013387
Author:
David S. Moore, George P. McCabe, Bruce A. Craig
Publisher:
W. H. Freeman