of a proton in a slow, rate-limiting step gives an anion which then expels the leaving group from the adjacent carbon. The reaction is particularly suited to the elimination of substrates which contain poor leaving groups two carbons removed from a carbonyl group. The poor leaving group disfavors the alternative E1 and E2 reactions, and the carbonyl group helps to stabilize the anion via resonance. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions 20 OH H₂O :OH H3C Previous Next> OH H CH3 H3C CH3 +

Organic Chemistry
8th Edition
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Chapter8: Haloalkanes, Halogenation, And Radical Reactions
Section: Chapter Questions
Problem 8.21P
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[References]
Alkyl halides undergo nucleophilic substitution and elimination reactions. When the kinetics of the reaction are measured, if the rate of the reaction is found to be
dependent only upon the concentration of the alkyl halide the reaction is first order. The substitution reaction is thus termed SN1, and the elimination reaction is
termed E1. These reactions are unimolecular and occur in two steps. The first step is rate-limiting and involves the loss of the leaving group to form a carbocation.
In the second, fast, step the nucleophile adds to the carbocation in the SN1 reaction or elimination occurs to give an alkene in the E1 reaction. Because the
carbocation is planar, the nucleophile can add to either face and therefore racemization is usually observed although solvent effects can influence this somewhat. E1
elimination follows Zaitsev's rule and typically yields the most substituted alkene as the major product.
Conditions which favor the SN1/E1 pathway include the use of a weak nucleophile and a polar protic solvent. The same reaction conditions apply for both SN1 and
E1, therefore these reactions will compete. It is usually difficult to predict which pathway, substitution or elimination, will predominate and so a mixture of products
is frequently observed.
In contrast to the E1 reaction which involves a carbocation intermediate, the E1cB reaction takes place through a carbanion intermediate. Base-induced abstraction
of a proton in a slow, rate-limiting step gives an anion which then expels the leaving group from the adjacent carbon. The reaction is particularly suited to the
elimination of substrates which contain poor leaving groups two carbons removed from a carbonyl group. The poor leaving group disfavors the alternative E1 and E2
reactions, and the carbonyl group helps to stabilize the anion via resonance.
Draw curved arrows to show the movement of electrons in this step of the mechanism.
Arrow-pushing Instructions
20
OH
H₂O
он
H3C
Previous Next>
F11
OH
H
XI
CH3
H3C
Cengage Learning Cengage Technical Support
CH3
+
F9
Transcribed Image Text:[References] Alkyl halides undergo nucleophilic substitution and elimination reactions. When the kinetics of the reaction are measured, if the rate of the reaction is found to be dependent only upon the concentration of the alkyl halide the reaction is first order. The substitution reaction is thus termed SN1, and the elimination reaction is termed E1. These reactions are unimolecular and occur in two steps. The first step is rate-limiting and involves the loss of the leaving group to form a carbocation. In the second, fast, step the nucleophile adds to the carbocation in the SN1 reaction or elimination occurs to give an alkene in the E1 reaction. Because the carbocation is planar, the nucleophile can add to either face and therefore racemization is usually observed although solvent effects can influence this somewhat. E1 elimination follows Zaitsev's rule and typically yields the most substituted alkene as the major product. Conditions which favor the SN1/E1 pathway include the use of a weak nucleophile and a polar protic solvent. The same reaction conditions apply for both SN1 and E1, therefore these reactions will compete. It is usually difficult to predict which pathway, substitution or elimination, will predominate and so a mixture of products is frequently observed. In contrast to the E1 reaction which involves a carbocation intermediate, the E1cB reaction takes place through a carbanion intermediate. Base-induced abstraction of a proton in a slow, rate-limiting step gives an anion which then expels the leaving group from the adjacent carbon. The reaction is particularly suited to the elimination of substrates which contain poor leaving groups two carbons removed from a carbonyl group. The poor leaving group disfavors the alternative E1 and E2 reactions, and the carbonyl group helps to stabilize the anion via resonance. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions 20 OH H₂O он H3C Previous Next> F11 OH H XI CH3 H3C Cengage Learning Cengage Technical Support CH3 + F9
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