One equivalent of 1,3-butadiene reacts with the quinone below to produce a single product. Why is there only one product, when there are several possible dienophiles in the quinone? * CH3 One of the double bonds is more reactive because it has the methyl group, an electron donating substituent. One of the double bonds is more reactive because it does not have the methyl group, an electron donating substituent The methyl group is a good leaving group, which eventually bubbles out of the solution as methane gas. Therefore, the quinone transforms into a symmetrical quinone before it reacts with the diene. Two equivalents of the unsymmetrical quinone react together to form a symmetrical quinone containing methyl groups on all four carbons.

Organic Chemistry
9th Edition
ISBN:9781305080485
Author:John E. McMurry
Publisher:John E. McMurry
Chapter14: Conjugated Compounds And Ultraviolet Spectroscopy
Section14.SE: Something Extra
Problem 41AP: Although the Diels–Alder reaction generally occurs between an electronrich diene and an...
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One equivalent of 1,3-butadiene reacts with the quinone below to produce a
single product. Why is there only one product, when there are several possible
dienophiles in the quinone? *
CH3
One of the double bonds is more reactive because it has the methyl group, an electron
donating substituent.
One of the double bonds is more reactive because it does not have the methyl group,
an electron donating substituent
The methyl group is a good leaving group, which eventually bubbles out of the
solution as methane gas. Therefore, the quinone transforms into a symmetrical
quinone before it reacts with the diene.
Two equivalents of the unsymmetrical quinone react together to form a symmetrical
quinone containing methyl groups on all four carbons.
Transcribed Image Text:One equivalent of 1,3-butadiene reacts with the quinone below to produce a single product. Why is there only one product, when there are several possible dienophiles in the quinone? * CH3 One of the double bonds is more reactive because it has the methyl group, an electron donating substituent. One of the double bonds is more reactive because it does not have the methyl group, an electron donating substituent The methyl group is a good leaving group, which eventually bubbles out of the solution as methane gas. Therefore, the quinone transforms into a symmetrical quinone before it reacts with the diene. Two equivalents of the unsymmetrical quinone react together to form a symmetrical quinone containing methyl groups on all four carbons.
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