Use the graphical method to construct the shear-force diagram and identify the magnitude of the largest shear force (consider bothpositive and negative). The ground reactions at the wall of the cantilever are provided.L1= 14.00 ftL2 = 7.75 ftVc = 87.00 kipsMc = 621.875 kip-ft20 kips70 kips12 kips/ft6 kips/ftMcAВL1L299.00 kipsO 110.00 kipsO 75.00 kipsO 64.00 kipsO 87.00 kips

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Answered: onstruct the shear-force diagram and…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Answer p1 and Part 2: Determine the shear force acting at each of the following locations:(a) x = 11.0- ft (i.e., just to the left of point B)(b) x = 11.0+ ft (i.e., just to the right of point B)(c) x = 28.5 ftNote that x = 0 at support A. When entering your answers, use the shear-force sign convention detailed in Section 7.2.Answers: a) V = ____ kips b) V = ____ kips c) V = ____ kips Part 3: Determine the bending moment acting at each of the following locations:(a) x = 11.0 ft (i.e., at point B)(b) x = 28.5 ftNote that x = 0 at support A. When entering your answers, use the bending-moment sign convention detailed in Section 7.2. Answers: a) M = ____ kips-ft b) M = ____ kips-ft Part 4: Use your shear-force and bending-moment diagrams to determine the maximum bending moment, Mmax, and its location, xmax. Use the bending-moment sign convention detailed in Section 7.2.Answers: Mmax = ____ kips-ft xmax = ____ ft
Downloads/ * Practice problem 2 Determine the location of the shear centre O of the thin-walled member of uniform thickness having the cross-section shown. [Ans. 5a/7] UNIVERSITY OF LIVERPOOL $ 4 € R LL F % 5 T G 40 6 Y & O. 7 T Second moment of area liyi U E H J 2a 8 S B K O O L P [ = www.check-p www.check-plag This site was upc via Microsoft Edge delete backspace #
A.) It is the boundary condition for fixed support Choices: Both choices Y=0 Y’=0 Either of the choices B.) It is a type of simple stress acting parallel to an area Choices: Flexural stress Shear stress Axial stress Bearing stress C.) For concentric row of bolts in a coupling connection, the shear deformations in the bolts is proportional to the: Choices Modulus of rigidity Diameter of bolt circle Radial distance Number of bolts note: please help us in the word meaing sample problems thank you
The Airy stress function for a cantilever beam loaded by a force applied at the opposite side to the built-in end is given by p=Axy 3 where the x coordinate runs along the length of the beam, the y coordinate runs along the width of the beam and A is an arbitrary constant which can be determined through application of boundary conditions. Which equation gives the shear stresses, ? O 0 O 6Axy O-3Ay² O-6Axy
We will use both shearing and bearing analysis to determine the quantities of rivets needed to fasten BC and BE. We can determine two values then choose what will be more safe. ■ For Member BC: ■ Based on Shearing: V T == ■ Av Based on Bearing: P Ab 70MPa = 96000 N .n. (19) ²x n 1/4. π n = 4.84 5 rivets 96000 N (19mm) (6mm) xn 140MPa n = 46.015≈ 7 rivets For member BC, we must use 7 rivets since we must need a minimum of 7 rivets to resist bearing stress produced by the connection. If we only use 5 rivets, then the bearing stress will become 168.42 MPa. It will result to failure since the allowable bearing stress is only 140 Mpa. ■ For member BE: (Practice at Home) Pac EXAMPLE: 5. The figure shows a roof truss and the detail of the riveted connection at joint B. Using allowable stresses of t = 70 MPa and ob= 140 MPa, how many 19-mm diameter rivets are required to fasten member BC to the gusset plate? Member BE? What is the largest average tensile or compressive stress in BC and BE? Say…
strength of material MENG222 Please solve the problem step by step and make your line clear and don't forget FBD and show me your step Please make sure your answer is correct please p1=123 p2=12
Learning Goal: To calculate the shear stress at a point in the web of an l- beam section subjected to a shear force. When a beam section is subjected to a shear load, a shear stress distribution is developed on the section. The distribution of the shear stress is not linear. Elasticity theory can be used to calculate the shear stress at any point. However, a simpler method can be used to calculate the average shear stress across the width of the section, a distance y above or below the neutral axis. The average VQ shear stress is given by T = Here V is the shear It force on the section, I is the moment of inertia of the entire section about the neutral axis, and ₺ is the width of the section at the distance y where the shear stress is being calculated. Q is the product of the area of the section above (or below) y and the distance from the neutral axis to the centroid of that area (Figure 1). In short, Qis the moment of the area about the neutral axis. Figure 1 of 1 An I-beam has a…
PRIOR ANSWERS: Reaction Forces: By = 76.809 Cy = 15.94 Shear Forces: V (× = 10.5- ft (i.e., just to the left of support B)) = -36.75 kips V ( x = 10.5+ ft (i.e., just to the right of support B)) = 40.059 kips V (x = 25.5 ft) = -12.441 kips V (x = 26.5- ft (i.e.. just to the left of support C))= = -15.941 kips Bending moment: M (x = 10.5 ft (i.e., at support B)) = -192.9375 kips-ft M (x = 25.5 ft) = 14.1975 kips-ft
reactions, V-vertical forces xample. Drau the shear force and Sinding mamemts 1.6KN 2.0kN 1.5kN HA 0.8m 1.2m 1m 1m
A (160+Reg. No.) kN force is applied as shown at the end of a hot-rolled steel beam. Neglecting the effect of fillets and of stress concentrations, perform calculations in MS excel or MATLAB for the principal stresses in the beam to satisfy a design specification that they be equal to or less than 150 MPa. If the principal stresses are more than the given value, what would you change in the beam so that satisfy the required stresses. 210 mm 13 mm a 1035 mm 110 mm 160kN +Reg No. 0.4m (b) (a) Figure: Hot-rolled cantilever steel beam a) 3D view of the beam b) Cross-section of the beam
5. Determine the diameter of a tensile member of a circular cross-section. The following data is given : Maximum tensile load = 10 kN; Maximum compressive load = 5 kN; Ultimate tensile strength = 600 MPa; Yield point = 380 MPa; Endurance limit = 290 MPa; Factor of safety = 4; Stress concentration [Ans. 24 mm] factor = 2.2
3. Design the cross-sections of the rods 25 to to 7. Initial data Results Sche -ma Distance Load Force Axial forces multipliers F(kN) N (cm) (1) Beta Beta 2 N1 N3 1 25 300 -4 48 -2.12 1.00 F F

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onstruct the shear-force diagram and identify the magnitude of the largest shear force (conside ound reactions at the wall of the cantilever are provided.