Answered: ormic acid (0.24mol) is placed in 2L of…

ormic acid (0.24mol) is placed in 2L of water and undergoes the following reaction:HCHO2(aq)+H2O(l) - H3O+(aq)+ CHO2-(aq) Kc= 2.1*10-4.

Principles of Modern Chemistry

8th Edition

ISBN:9781305079113

Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Chapter16: Solubility And Precipitation Equilibria

Section: Chapter Questions

Problem 70AP

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Question

formic acid (0.24mol) is placed in 2L of water and undergoes the following reaction:HCHO₂(aq)+H₂O(l) - H₃O⁺(aq)+ CHO₂^-(aq) K_c= 2.1*10^-4.

(a) use your solver to calculate the equilibrium concentration of hydronim ion in this solution? (b) Approximate the answer to this problem by assuming x is small. show your work.

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