Oxygen gas can be prepared by heating potassium chlorate according to the following equation: 2KClO3(s)2KCl(s) + 3O2(g)   In an experiment, the O2 gas formed is collected over water in a flask where the total pressure is 757 mm Hg and the temperature is 16.0°C, at which temperature the vapor pressure of water is 14mm

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Chapter5: The Gaseous State
Section: Chapter Questions
Problem 5.117QP: Liquid oxygen was first prepared by heating potassium chlorate, KClO3, in a closed vessel to obtain...
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Oxygen gas can be prepared by heating potassium chlorate according to the following equation:

2KClO3(s)2KCl(s) + 3O2(g)  
In an experiment, the O2 gas formed is collected over water in a flask where the total pressure is 757 mm Hg and the temperature is 16.0°C, at which temperature the vapor pressure of water is 14mm Hg.


(1) What is the partial pressure of O2 in the flask? mm Hg.

(2) If the wet O2 gas occupies a volume of 6.15 L, how many moles of O2 are formed? mol

 

Oxygen gas can be prepared by heating potassium chlorate according to the following equation:
2KCIO3(s)-
→2KCI(s) + 302(g)
to reaction
gas
vessel
In an experiment, the O, gas formed is collected over water in a
flask where the total pressure is 757 mm Hg and the temperature
is 16.0°C, at which temperature the vapor pressure of water is 14
mm Hg.
(1) What is the partial pressure of O, in the flask?
mm Hg.
(2) If the wet 02 gas occupies a volume of 6.15 L, how many moles of O, are formed?
mol
Transcribed Image Text:Oxygen gas can be prepared by heating potassium chlorate according to the following equation: 2KCIO3(s)- →2KCI(s) + 302(g) to reaction gas vessel In an experiment, the O, gas formed is collected over water in a flask where the total pressure is 757 mm Hg and the temperature is 16.0°C, at which temperature the vapor pressure of water is 14 mm Hg. (1) What is the partial pressure of O, in the flask? mm Hg. (2) If the wet 02 gas occupies a volume of 6.15 L, how many moles of O, are formed? mol
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