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P = P2O5 × 0.44 P2O5 = P × 2.29 K = K2O × 0.83 K2O = K × 1.21 1 tonne = 1,000 kg 1 ha = 10,000 m2 Using the conversions above calculate :  How much N, P and K are in a 15 kg bag of 0-46-0?  How much N and P2O5 are in half tonne of DAP (18-46-0)?  How much P and N are in quarter tonne of DAP (18-46-0)?

P = P2O5 × 0.44 P2O5 = P × 2.29 K = K2O × 0.83 K2O = K × 1.21 1 tonne = 1,000 kg 1 ha = 10,000 m2 Using the conversions above calculate :  How much N, P and K are in a 15 kg bag of 0-46-0?  How much N and P2O5 are in half tonne of DAP (18-46-0)?  How much P and N are in quarter tonne of DAP (18-46-0)?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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  • P = P2O5 × 0.44
  • P2O5 = P × 2.29
  • K = K2O × 0.83
  • K2O = K × 1.21
  • 1 tonne = 1,000 kg
  • 1 ha = 10,000 m2

Using the conversions above calculate : 

  1. How much N, P and K are in a 15 kg bag of 0-46-0? 
  2. How much N and P2O5 are in half tonne of DAP (18-46-0)? 
  3. How much P and N are in quarter tonne of DAP (18-46-0)?
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