Name of a report STRENGTH OF MATERIALS LABORATORY COMPRESSION TEST Hi sir, I know your precious time will be taken, please get a report. I want you to explain to me one or two pages is enough for me, dear sir, by solving the last schedule, may God help you and grant you God bless you P= The magnitude of the applied force (N).AL = amount of shrinkage of the sample (mm).- Relationship between agitation and stressAccording to Hooke's law, the stress is directly proportional to the strain, and theproportionality coefficient is called the modulus of elasticity or the Youngsmodulus (Modulus of Elasticity).•O =ExE...........3Ain..6......AcLoxAoAcLo+AL€r = In(1 + €e)Shrinkage percentage % --LSwelling percentage % -dLo H,-99.8mm , L,-40mm A.- 1Gagm?W.-40mmForceALE-a/eAET(N)(mm)0.000200401 13098.750.001753507 1782.142857 1597.19930.002955912 1691.525424 1595.284481599.679423 2.625526052 0.0002003813.130479709 0.00175197142000.022.62550000.175 3.12580000.295 55.014779559 0.002951552120000.352.6250.000200401 13098.751599.679423 2.625526052 0.000200381160000.420000 0.45240000.5Strength of MaterialsDr. Maad Abdullah HusseinAL-ESRAA UNIVERSITY COLLEGE28000 0.55320000.6360000.65400000.7440000.75480000.8520000.87560000.9360000640001.07680001.15800001.37840001.47880001.57920001.77960002.07966002.45880002.65860002.8840002.9820003800003.07720003.25H- 97.75mmL-40.9 mm, W- 40.55 mm 1. IntroductionA compression test is conducted in a manner similar to tensile test, except that theforce is compressive and the specimen contracts along the direction of stress. Byconvention, a compressive force is taken to be negative, which yields a negativestress, compressive strains are also negative. Tensile tests are more commonbecause they are easier to perform; also, for most materials used in structuresapplication, very little additional information is obtained from compressive test.STRENGTH OF M ATERIALSABORAT ORY COMPRESSION TEST2. TheoryWhen a material is subjected to compressive loading, the relationship betweenstress and strain is similar to that obtained for a tensile loading. Up to a certainvalue of stress, the material behaves elastically, i.e. stress is in proportion to strain.Beyond this value, plastic flow starts, i.e. more strain starts than happening inelastic limit for any increment value of loading. It is seen that a compression test ismore difficult to be conducted than standard tensile test due to (i) specimen musthave larger cross-sectional area to resist any buckling due to bending, (ii) thespecimen undergoing strain hardening as deformation proceeds, and (iii) cross-section of the specimen increases with deformation, thereby requiring substantialincrease in the required load. The lateral instability due to buckling action can beavoided by keeping the ratio of height (h) to diameter (d) of the specimen less than2. The compressive strength essentially depends open h' to d' ratio. Hence,higher is 'h' to 'd' ratio, lower is the compressive strength.(-) strain(*) strain- The compressive test is the opposite of the tensile test, as follows:1- The area under pressure is square, rectangular or eircular.2- In this test, we calculate a percentage of swelling and a percentage ofcontraction.3- This experiment is conducted on brittle materials.4- In this experiment there are no yield points.3. Objective of the ExperimentObserve the stress strain behavior of the metals under compression load.Determine the strength and other properties of various materials.Studying the relationship between force (p) and contraction.Proving and studying the relationship between strain (E) and stress (6).Studying the concept of mechanical properties of solid materials.4. Difference Between Tensile and Compression TestTension test is normally conducted to obtain the mechanical properties ofMetals. It is the primary test used for quality control and the basis foracceptance and refusal of metallie products used in construction and otheruses.Compression test is used to obtain the mechanical properties and is the basisacceptance and refusal of brittle nonmetallic and other materials that havevery low strength in tension like concrete, wood, masonry, etc.

Question

Name of a report STRENGTH OF MATERIALS LABORATORY COMPRESSION TEST  Hi sir, I know your precious time will be taken, please get a report. I want you to explain to me one or two pages is enough for me, dear sir, by solving the last schedule, may God help you and grant you God bless you P= The magnitude of the applied force (N).AL = amount of shrinkage of the sample (mm).- Relationship between agitation and stressAccording to Hooke's law, the stress is directly proportional to the strain, and theproportionality coefficient is called the modulus of elasticity or the Youngsmodulus (Modulus of Elasticity).•O =ExE...........3Ain..6......AcLoxAoAcLo+AL€r = In(1 + €e)Shrinkage percentage % --LSwelling percentage % -dLo> H,-99.8mm , L,-40mm> A.- 1Gagm?W.-40mmForceALE-a/eAET(N)(mm)0.000200401 13098.750.001753507 1782.142857 1597.19930.002955912 1691.525424 1595.284481599.679423 2.625526052 0.0002003813.130479709 0.00175197142000.022.62550000.175 3.12580000.295 55.014779559 0.002951552120000.352.6250.000200401 13098.751599.679423 2.625526052 0.000200381160000.420000 0.45240000.5Strength of MaterialsDr. Maad Abdullah HusseinAL-ESRAA UNIVERSITY COLLEGE28000 0.55320000.6360000.65400000.7440000.75480000.8520000.87560000.9360000640001.07680001.15800001.37840001.47880001.57920001.77960002.07966002.45880002.65860002.8840002.9820003800003.07720003.25H- 97.75mmL-40.9 mm, W- 40.55 mm 1. IntroductionA compression test is conducted in a manner similar to tensile test, except that theforce is compressive and the specimen contracts along the direction of stress. Byconvention, a compressive force is taken to be negative, which yields a negativestress, compressive strains are also negative. Tensile tests are more commonbecause they are easier to perform; also, for most materials used in structuresapplication, very little additional information is obtained from compressive test.STRENGTH OF M ATERIALSABORAT ORY COMPRESSION TEST2. TheoryWhen a material is subjected to compressive loading, the relationship betweenstress and strain is similar to that obtained for a tensile loading. Up to a certainvalue of stress, the material behaves elastically, i.e. stress is in proportion to strain.Beyond this value, plastic flow starts, i.e. more strain starts than happening inelastic limit for any increment value of loading. It is seen that a compression test ismore difficult to be conducted than standard tensile test due to (i) specimen musthave larger cross-sectional area to resist any buckling due to bending, (ii) thespecimen undergoing strain hardening as deformation proceeds, and (iii) cross-section of the specimen increases with deformation, thereby requiring substantialincrease in the required load. The lateral instability due to buckling action can beavoided by keeping the ratio of height (h) to diameter (d) of the specimen less than2. The compressive strength essentially depends open h' to d' ratio. Hence,higher is 'h' to 'd' ratio, lower is the compressive strength.(-) strain(*) strain- The compressive test is the opposite of the tensile test, as follows:1- The area under pressure is square, rectangular or eircular.2- In this test, we calculate a percentage of swelling and a percentage ofcontraction.3- This experiment is conducted on brittle materials.4- In this experiment there are no yield points.3. Objective of the ExperimentObserve the stress strain behavior of the metals under compression load.Determine the strength and other properties of various materials.Studying the relationship between force (p) and contraction.Proving and studying the relationship between strain (E) and stress (6).Studying the concept of mechanical properties of solid materials.4. Difference Between Tensile and Compression TestTension test is normally conducted to obtain the mechanical properties ofMetals. It is the primary test used for quality control and the basis foracceptance and refusal of metallie products used in construction and otheruses.Compression test is used to obtain the mechanical properties and is the basisacceptance and refusal of brittle nonmetallic and other materials that havevery low strength in tension like concrete, wood, masonry, etc.

Accepted Answer

In this problem, we will complete the table for four forces.
Calculate the parameters for force…