P1A.5 Deduce the relation between the pressure and mass density, p, of a perfect gas of molar mass M. Confirm graphically, using the following data on methoxymethane (dimethyl ether) at 25°C, that perfect behaviour is reached at low pressures and find the molar mass of the gas. p/kPa 12.223 25.20 36.97 60.37 85.23 101.3 p/(kgm) 0.225 0.456 0.664 1.062 1.468 1.734

P1A.5 Deduce the relation between the pressure and mass density, p, of a perfect gas of molar mass M. Confirm graphically, using the following data on methoxymethane (dimethyl ether) at 25°C, that perfect behaviour is reached at low pressures and find the molar mass of the gas. p/kPa 12.223 25.20 36.97 60.37 85.23 101.3 p/(kgm) 0.225 0.456 0.664 1.062 1.468 1.734

Physical Chemistry

2nd Edition

ISBN:9781133958437

Author:Ball, David W. (david Warren), BAER, Tomas

Publisher:Ball, David W. (david Warren), BAER, Tomas

Chapter1: Gases And The Zeroth Law Of Thermodynamics

Section: Chapter Questions

Problem 1.51E: Numerically evaluate for one mole of methane acting as a van der Waals gas at a T = 298 K and V =...

See similar textbooks

Similar questions

Numerically evaluate for one mole of methane acting as a van der Waals gas at a T = 298 K and V = 25.0 L and b T = 1000 K and V = 250.0 L. Comment on which set of conditions yields a number closer to that predicted by the ideal gas law. pVT,n
P1A.5 Deduce the relation between the pressure and mass density, ρ, of a perfect gas of molar mass M. Confirm graphically, using the following data on methoxymethane (dimethyl ether) at 25 °C, that perfect behaviour is reached at low pressures and the molar mass of the gas. p/kPa 12.223 25.20 36.97 60.37 85.23 101.3 ρ/(kgm–3) 0.225 0.456 0.664 1.062. 1.468 1.734
Gallium melts just above room temperature and is liquid overa very wide temperature range 130–2204 °C2, which means itwould be a suitable fluid for a high-temperature barometer.Given its density, dGa = 6.0 g>cm3, what would be the heightof the column if gallium is used as the barometer fluid andthe external pressure is 9.5 * 104 Pa?
The second virial coefficient of methane can be approximated by the empirical equation B(T) = a + e-c/T^2, where a = −0.1993 bar−1, b = 0.2002 bar−1, and c = 1131 K2 with 300 K < T < 600 K. What is the Boyle temperature of methane?
Determine the partial molar volume of a component of a gas mixture based on the provided equation of state. When PV (1 – bP) = n2RT, the constant b is taken into consideration.
A chimney gas has the following composition by volume: 9.5% C02, 0.2% CO, 9.6% O2 and 80.7% N2. Using the ideal gas law, calculate a. its composition by weightb. Volume occupied by 1 kg of the gas at 270C and 750 torrsc. density of the gas mixture (kg/m3) at conditions of b)d. specific gravity of the mixture.
What mass of C2H4 is needed to produce 56L of CO2(g) at 315k and 1.00ATM in a combustion reaction with excess oxygen gas
A fuel has the following volumetric analysis: CH4 = 68% C2H6 = 32% Assume complete combustion with 15% excess aur at 101.325 kPa and 27 degrees dry bulb temperature. What is the total moles in the products of combustion?
For an ideal gas obeying the ideal gas law, P = nRT/V , where R is the gas constant. Write the total differential dz and evaluate the partial derivatives
Gallium melts just above room temperature and is liquid overa very wide temperature range (30–2204 °C), which means itwould be a suitable fluid for a high-temperature barometer.Given its density, dGa = 6.0 g/cm3, what would be the heightof the column if gallium is used as the barometer fluid andthe external pressure is 9.5 x104 Pa?
100.0 g of propyne (C3H4) (g) is burnt in a 30.0 L rigid vessel containing pure O2 (g) at P = 10.00 bar and an initial temperature of 25.0 °C. At the end of the reaction the temperature of the vessel is 250. °C. At the end of the reaction, what are the partial pressures (in bar) of CO2 (g) and O2 (g)?
Rearrange the van der Waals equation of state, p = nRT/(V − nb) − n2a/V2(Topic 1C) to give an expression for T as a function of p and V (with n constant). Calculate (∂T/∂p)V and confirm that (∂T/∂p)V = 1/(∂p/∂T)V.