Forgot to put the units they are asking for on the previous submission. Am I doing this correctly? A gaseous sample of molecules, with a molar mass of 87.9 g/mol, is contained in a cylinder at a temperature of 362. K and pressure of 101.9 kPa. The collision cross section of a molecule is 0.73 nm2 The collision freqency, z, of the gas under these conditions is ____________ s-1.

Forgot to put the units they are asking for on the previous submission. Am I doing this correctly? A gaseous sample of molecules, with a molar mass of 87.9 g/mol, is contained in a cylinder at a temperature of 362. K and pressure of 101.9 kPa. The collision cross section of a molecule is 0.73 nm2 The collision freqency, z, of the gas under these conditions is ____________ s-1.

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter7: Statistical Data Treatment And Evaluation

Section: Chapter Questions

Problem 7.17QAP

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Estimate the Km and vmax from the data. [S] (M) Velocity (µM/min) 2.5 x 10-6 28 .00001 70 .00004 112 .0001 128 .002 139 .01 140 Km=.00001 vmax=140 Km=.002 vmax=112 Km=.01 vmax=140 Km=.00001 vmax=70
1. Which of the following is NOT a true representation of the Lineweaver-Burk equation? Group of answer choices a. y-intercept = -1/Vmax b. x-intercept = -1/Km c. y = 1/V0 d. x = 1/[S] e. slope = Km/Vmax 2. If the y-intercept of a Lineweaver-Burk (double reciprocal) plot = 39.37 (sec/millimole) and the slope = 75.3 L/sec, Vmax equals: Group of answer choices a. 75.3 millimoles/sec. b. 0.0254 millimoles/sec. c. 0.523 millimoles/sec. d. 39.4 millimoles/sec. 3. Which of the following is true regarding allosteric enzyme behavior?Group of answer choices a. Allosteric enzymes are rarely important in the regulation of metabolic pathways. b. An allosteric effector binds reversibly on the surface of the enzyme. c. An hyperbolic representation of the relation initial velocity vs [S] is a specific characteristic of an allosteric enzyme behavior. d. Michaelis-Menten kinetics model the kinetic behavior of allosteric enzymes.
Given the following data, calculate the 95% confidence interval. 0.452 0.453 0.448 0.456 0.458 Average = 0.4534 St. Dev. = 0.003847 1) 0.453 ± 0.004 2) 0.453 ± 0.005 3) 0.4534 ± 0.0048 4) 0.4534 ± 0.0037 5) 0.4534 ± 0.0038
A 120. MW coal plant wants to add a SOXemissions control system to reduce its emissions. The emission control system has a capitalcost of $815 per kW and reduces SOX emissions by 98% to 0.0918 kg/MWh. Assume thelifetime of the emission control system is 20 years and the power plant produces 650GWh/y. a)What is the annualized cost of this system in dollars per year if the discount rate (interestrate) is 7.0 percent/year? What if the discount rate is 4.0 percent/year? b)What is the cost per 1.0399 x 104 kWh of electricity usage (the average annual U.S.residential electricity consumption in 2017 according to the EIA) at each of the discountrates specified in part a? c)What is the cost per metric ton of SOx removed at each of the discount rates specified inpart a?
Express 20,000ppb as a percentage strength A. 2% B. 0.02% C. 0.00002% D. 0.002%
Calculate the specific volume, α (cm3/gm), using the following equation and the values of constants and conversion factors provided. α = (RT)/p Where R = 2.8704 x 106 erg/gm(˚K), T = 10˚C, and p = 1000 millimars (mb). All of the conversion factors you will need are: 1 mb = 103 dynes/cm2 ˚K = 273˚ + ˚C erg = dyne(cm) a. α = 8.123 x 109 cm3/gm b. α = 8.123 x 102 cm3/gm c. α = 2.8704 x 104 cm3/gm d. α = 2.8704 x 106 cm3/gm
Chemistry Fraction no. Elution Vol. (mL) Abs (λ = 410) Fraction no. Elution Vol. (mL) Abs (λ = 410) 1 (PB pH 6.0) 1 0.0050 11 11 0.0041 2 2 0.0032 12 12 0.0060 3 3 0.0040 13 13 0.0064 4 4 0.0064 14 14 0.0063 5 5 0.0067 15 15 0.1109 6 6 0.0067 16 16 2.8902 7 7 0.0050 17 17 0.8500 8 (PB pH 8.0) 8 0.0049 18 18 0.2019 9 9 0.0052 19 19 0.0378 10 10 0.0050 20 20 0.0073 Use the data above to plot an elution profile, in which the absorbance is on Y-axis, and elution volume (volume = fraction number) is on X-axis. The elution profile must indicate at (1) which point the pH change occurred, (2) the fraction(s) which contain the highest myoglobin content, and (3) the maximum absorbance detected.
If 35,000 kg of whole milk containing 4% fat is to be separated in a 6-hour period into skim milk with 0.45% fat and cream with 45% fat, what are the mass flow rates of the two output streams from a continuous centrifuge which accomplishes this separation? (Ans; Cream=464.8335kg/h, Skim milk= 5368.4998kg/h)
Please answer fast it’s very important and urgent I say very urgent so please answer super super fast please For the image attached For 1. a Mass of metal: Trial 1 is 35.0228 g Trial 2 is 35.0915 g Trial 3 is 34.0821 g Mass of water: Trial 1 is 20.0177 g Trial 2 is 20.0250 g Trial 3 is 20.0168 g For delta t of water: Trial 1 is 15.5 C Trial 2 is 15.7 C Trial 3 is 15.1 C For delta t of metal Trial 1 is 80.1 C Trial 2 is 80.2 C Trial 3 is 79.5 C For B my calculated Specific heat is: Trial 1 is 0.462 Trial 2 is 0.467 Trial 3 is 0.466
You are absolutely the BEST. Finally someone that dosen't calculate this exercise as 836f66dgsffjgvkik!!!! I understand everything you did, but I have one question. Some experts says that km can be calculated by saying Vmax from date divided by 2 and then they find Km by going down on x-axis on the graph. But, you used the MM equation, to solve for Km. Is both method the same? Or is one of them more precise than the other? *And if theres no need to reply back after you answering my question, then I will thank you again for your help. I have more these types of exam questions that I will probably upload later, and I hope someone like you will look at it.
Chemistry (i) For T = 298K ΔG° = -8.314 x 298 x ln (2.83x10-3) = 14.524 KJ/mol (ii) For T = 308.15K ΔG° = -8.314 x 308.15 x ln (9.619x10-3) = 11.891 KJ/mol (iii) For T = 318.15K ΔG° = -8.314 x 318.15 x ln (3.14x10-2) = 9.147 KJ/mol (iv) For T = 328.15K ΔG° = -8.314 x 328.15 x ln (8.82x10-2) = 6.621 KJ/mol (v) For T = 338.15K ΔG° = -8.314 x 338.15 x ln (2.42x10-1) = 3.990 KJ/mol Based on the measured ΔG° values, is this equilibrium spontaneous at room temperature? Which factor, entropy, or enthalpy, has the greater impact on spontaneity in this case? Explain your answers.
5.61 x 10^-12 is the ksp