P34 Th→ 234 Pa + fe 90 This is an example of: (circle one) 91 Alpha decay Beta decay Positron emission Electron capture 92U. P38U → 234 Th + He "his is an example of: (circle one) Alpha decay Beta decay Positron emission Electron capture 311 53 his is an example of: (circle one) -1' Alpha decay Beta decay Positron emission Electron capture 251Cf, 247 Cm + 98 96 his is an example of: (circle one) Alpha decav Beta decay Positron emission Electron capture

College Physics
1st Edition
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:Paul Peter Urone, Roger Hinrichs
Chapter31: Radioactivity And Nuclear Physics
Section: Chapter Questions
Problem 41PE: (a) Calculate the energy released in the a decay of 238U. (b) What fraction of the mass at a single...
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Choose the decay.
а.
234 Th
90
234 Pa + je
91
This is an example of: (circle one)
Alpha decay
Beta decay
Positron emission
Electron capture
b.
238 U → 234 Th + He
92
This is an example of: (circle one)
Alpha decay
Beta decay
Positron emission
Electron capture
c.
131,
53
This is an example of: (circle one)
Alpha decay
Beta decay
Positron emission
Electron capture
d.
247
251 Cf-
Cm +
96
98
This is an example of: (circle one)
Alpha decay
Beta decay
Positron emission
Electron capture
Transcribed Image Text:Choose the decay. а. 234 Th 90 234 Pa + je 91 This is an example of: (circle one) Alpha decay Beta decay Positron emission Electron capture b. 238 U → 234 Th + He 92 This is an example of: (circle one) Alpha decay Beta decay Positron emission Electron capture c. 131, 53 This is an example of: (circle one) Alpha decay Beta decay Positron emission Electron capture d. 247 251 Cf- Cm + 96 98 This is an example of: (circle one) Alpha decay Beta decay Positron emission Electron capture
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