Part A An object is moving along the -axis. At t = 0 it has velocity vor = 19.0 m/s. Starting at time t = 0 it has acceleration az = -Ct, where C has units of m/s. What is the value of C if the object stops in 8.00 s after t = 0? C = 0.594 m/s³ Submit Previous Answers v Correct Part B For the value of C calculated in the previous part, how far does the object travel during the 8.00 s? Express your answer with the appropriate units. HA ? * - 20 = Value Submit Previous Answers Request Answer

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter2: Motion In One Dimension
Section: Chapter Questions
Problem 6P: The position of a particle moving along the x axis varies in time according to the expression x =...
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Not sure how to get part B.

Part A
An object is moving along the a-axis. At t = 0 it has
velocity vor = 19.0 m/s. Starting at time t = 0 it has acceleration
az = -Ct, where C has units of m/s.
What is the value of C if the object stops in 8.00 s after t = 0?
C = 0.594 m/s
Submit
Previous Answers
Correct
Part B
For the value of C calculated in the previous part, how far does the object travel during the 8.00 s?
Express your answer with the appropriate units.
HA
?
x - xo =
Value
m
Submit
Previous Answers Request Answer
Transcribed Image Text:Part A An object is moving along the a-axis. At t = 0 it has velocity vor = 19.0 m/s. Starting at time t = 0 it has acceleration az = -Ct, where C has units of m/s. What is the value of C if the object stops in 8.00 s after t = 0? C = 0.594 m/s Submit Previous Answers Correct Part B For the value of C calculated in the previous part, how far does the object travel during the 8.00 s? Express your answer with the appropriate units. HA ? x - xo = Value m Submit Previous Answers Request Answer
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