Part A: Atomic Mass of Zinc 1. Mass of zinc 2. Temperature of water collected 3. Volume of water collected 4. Atmospheric Pressure 5. Vapor Pressure of water (see table 6. Corrected Pressure of H₂ Calculation to atm: 22.2_ C__295.4 380 mL 29.81 in Hg 19.8 mm Hg _738.2__mm Hg 0.994g K 0.38 L _758___mm Hg _0.971_atm

Chemistry: An Atoms First Approach
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ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
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Chapter8: Gases
Section: Chapter Questions
Problem 158CP
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I need calculation part only please do calculations as soon as possible experiment I already done do calculations 

Part A: Atomic Mass of Zinc
1. Mass of zinc
2. Temperature of water collected
3. Volume of water collected
4. Atmospheric Pressure
5. Vapor Pressure of water (see table
6. Corrected Pressure of H₂
Calculation to atm:
7. Moles of H₂
Calculation:
29.81 in Hg.
Calculation:
22.2_ "C_295.4___K
_380____ mL
10. Atomic mass of zinc from periodic table
11. Percent error
19.8 mm Hg
___738.2___ mm Hg
8. Moles of zinc (equals moles of H₂)
9. Experimental atomic mass of zinc (show calc:)
0.994g
0.38 L
_758__mm Hg
0.971_ atm
__0.0152 mol H2_
____0.0152 mol H2______
0.994 g/mol
65.38 g/mol
12. Using equation stoichiometry and the starting mass of zinc, calculate the mass of ZnCl₂
created.
_____136.286 g/mol______
Begin with the balanced equation:
Transcribed Image Text:Part A: Atomic Mass of Zinc 1. Mass of zinc 2. Temperature of water collected 3. Volume of water collected 4. Atmospheric Pressure 5. Vapor Pressure of water (see table 6. Corrected Pressure of H₂ Calculation to atm: 7. Moles of H₂ Calculation: 29.81 in Hg. Calculation: 22.2_ "C_295.4___K _380____ mL 10. Atomic mass of zinc from periodic table 11. Percent error 19.8 mm Hg ___738.2___ mm Hg 8. Moles of zinc (equals moles of H₂) 9. Experimental atomic mass of zinc (show calc:) 0.994g 0.38 L _758__mm Hg 0.971_ atm __0.0152 mol H2_ ____0.0152 mol H2______ 0.994 g/mol 65.38 g/mol 12. Using equation stoichiometry and the starting mass of zinc, calculate the mass of ZnCl₂ created. _____136.286 g/mol______ Begin with the balanced equation:
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