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Visited (Atomic masses: iron-56 = 55.9349 amu; hydrogen-1 = 1.0078 amu; mass of neutron = 1.0087 amu) HOW DO WE GET THERE? We must first calculate the mass defect (Am) for 5bFe. Since atomic masses (which include the electrons) are given, we must decide how to account for the electron mass: 55.9349 = mass of Fe atom = mass of nucleus + 26 m. 1.0078 = mass of H atom = mass of nucleus + me Thus, since a 56Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 - 26 m) - [26(1.0078 - m) + 30(1.0087)]. Solve for Am. amu

Visited (Atomic masses: iron-56 = 55.9349 amu; hydrogen-1 = 1.0078 amu; mass of neutron = 1.0087 amu) HOW DO WE GET THERE? We must first calculate the mass defect (Am) for 5bFe. Since atomic masses (which include the electrons) are given, we must decide how to account for the electron mass: 55.9349 = mass of Fe atom = mass of nucleus + 26 m. 1.0078 = mass of H atom = mass of nucleus + me Thus, since a 56Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 - 26 m) - [26(1.0078 - m) + 30(1.0087)]. Solve for Am. amu

Chemistry for Today: General, Organic, and Biochemistry
Chemistry for Today: General, Organic, and Biochemistry
9th Edition
ISBN:9781305960060
Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher:Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Chapter10: Radioactivity And Nuclear Processes
Section: Chapter Questions
Problem 10.8E
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26 Fe Visited (Atomic masses: iron-56 = 55.9349 amu; hydrogen-1 = 1.0078 amu; mass of neutron = 1.0087 amu) HOW DO WE GET THERE? We must first calculate the mass defect (Am) for 56Fe. Since atomic masses (which include the electrons) are given, we must decide how to account for the electron mass: 55.9349 = mass of Fe atom = mass of nucleus + 26 mẹ 1.0078 = mass of H atom = mass of nucleus + me Thus, since a 56Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 – 26 m2) – [26(1.0078 - me) + 30(1.0087)]. Solve for Am. Am = amu
Transcribed Image Text:26 Fe Visited (Atomic masses: iron-56 = 55.9349 amu; hydrogen-1 = 1.0078 amu; mass of neutron = 1.0087 amu) HOW DO WE GET THERE? We must first calculate the mass defect (Am) for 56Fe. Since atomic masses (which include the electrons) are given, we must decide how to account for the electron mass: 55.9349 = mass of Fe atom = mass of nucleus + 26 mẹ 1.0078 = mass of H atom = mass of nucleus + me Thus, since a 56Fe nucleus is "synthesized" from 26 protons and 30 neutrons, we see that Am = (55.9349 – 26 m2) – [26(1.0078 - me) + 30(1.0087)]. Solve for Am. Am = amu
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